An arctic weather balloon is filled with 28.5 L of helium gas inside a prep shed. The temperature inside the shed is 14. °C. The balloon is then taken outside, where the temperature is -35. °C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Round your answer to 3 significant digits. OL X S

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Transcription of Educational Content:

**Problem Statement:**

An arctic weather balloon is filled with 28.5 L of helium gas inside a prep shed. The temperature inside the shed is 14 °C. The balloon is then taken outside, where the temperature is −35 °C. Calculate the new volume of the balloon.

You may assume the pressure on the balloon stays constant at exactly 1 atm. Round your answer to 3 significant digits.

**Solution Steps:**

1. **Initial Conditions:**
   - Initial Volume (V₁) = 28.5 L
   - Initial Temperature (T₁) = 14 °C

2. **Final Conditions:**
   - Final Temperature (T₂) = −35 °C

3. **Assumptions:**
   - Pressure is constant at 1 atm.

4. **Conversion:**
   - Convert temperatures from Celsius to Kelvin:
     - T₁ = 14 °C + 273.15 = 287.15 K
     - T₂ = −35 °C + 273.15 = 238.15 K

5. **Use Charles's Law:**
   - Charles's Law Formula: \( \frac{V₁}{T₁} = \frac{V₂}{T₂} \)

6. **Calculation:**
   - Rearrange the formula to solve for V₂: 
     - \( V₂ = V₁ \times \frac{T₂}{T₁} \)
     - \( V₂ = 28.5 \, \text{L} \times \frac{238.15 \, \text{K}}{287.15 \, \text{K}} \)

7. **Result:**
   - Calculate the new volume V₂ and round to three significant digits.

**Interface Controls:**

- There is an input box labeled with "L" for inputting the calculated volume.
- There is a check button to verify the answer.
- Explanation and Check options are available for further guidance.

**Notice:**

For educational practice, it's crucial to understand the concepts of gas laws and how temperature conversions between Celsius and Kelvin are essential in these calculations.
Transcribed Image Text:### Transcription of Educational Content: **Problem Statement:** An arctic weather balloon is filled with 28.5 L of helium gas inside a prep shed. The temperature inside the shed is 14 °C. The balloon is then taken outside, where the temperature is −35 °C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Round your answer to 3 significant digits. **Solution Steps:** 1. **Initial Conditions:** - Initial Volume (V₁) = 28.5 L - Initial Temperature (T₁) = 14 °C 2. **Final Conditions:** - Final Temperature (T₂) = −35 °C 3. **Assumptions:** - Pressure is constant at 1 atm. 4. **Conversion:** - Convert temperatures from Celsius to Kelvin: - T₁ = 14 °C + 273.15 = 287.15 K - T₂ = −35 °C + 273.15 = 238.15 K 5. **Use Charles's Law:** - Charles's Law Formula: \( \frac{V₁}{T₁} = \frac{V₂}{T₂} \) 6. **Calculation:** - Rearrange the formula to solve for V₂: - \( V₂ = V₁ \times \frac{T₂}{T₁} \) - \( V₂ = 28.5 \, \text{L} \times \frac{238.15 \, \text{K}}{287.15 \, \text{K}} \) 7. **Result:** - Calculate the new volume V₂ and round to three significant digits. **Interface Controls:** - There is an input box labeled with "L" for inputting the calculated volume. - There is a check button to verify the answer. - Explanation and Check options are available for further guidance. **Notice:** For educational practice, it's crucial to understand the concepts of gas laws and how temperature conversions between Celsius and Kelvin are essential in these calculations.
Expert Solution
Step 1: Introduction to gas law

In the given question we have to calculate the new volume of the balloon by using Charles law. 

Charles states that the volume of gas directly proportional to the temperature at constant pressure.

Given data:

initial volume of helium gas in the balloon = 28.5 L

Initial temperature = 14 oC

Final temperature  = -35. oC


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