An aqueous solution contains 0.29 M ammonia. One liter of this solution could be converted into a buffer by the addition of: (Assume that the volume remains constant as each substance is added.) O 0.15 mol Ba(OH)2 O 0.30 mol NH¿Br O 0.30 mol HNO3 O 0.29 mol BaBr2 O 0.15 mol HNO3

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Chapter1: Chemical Foundations
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**Solution Buffering Instruction**

A one-liter aqueous solution contains 0.29 M ammonia.

To convert this solution into a buffer, you may add one of the following substances. Ensure that the solution's volume remains constant as each substance is added:

- 0.15 mol Ba(OH)\(_2\)
- 0.30 mol NH\(_4\)Br
- 0.30 mol HNO\(_3\)
- 0.29 mol BaBr\(_2\)
- 0.15 mol HNO\(_3\)

**Note:** It is important to understand how each addition impacts the solution's buffering capacity and its chemical equilibrium.
Transcribed Image Text:**Solution Buffering Instruction** A one-liter aqueous solution contains 0.29 M ammonia. To convert this solution into a buffer, you may add one of the following substances. Ensure that the solution's volume remains constant as each substance is added: - 0.15 mol Ba(OH)\(_2\) - 0.30 mol NH\(_4\)Br - 0.30 mol HNO\(_3\) - 0.29 mol BaBr\(_2\) - 0.15 mol HNO\(_3\) **Note:** It is important to understand how each addition impacts the solution's buffering capacity and its chemical equilibrium.
**Buffer Solution Formation with Hypochlorous Acid**

An aqueous solution contains **0.33 M hypochlorous acid**.

One liter of this solution could be converted into a buffer by the addition of:

(Assume that the volume remains constant as each substance is added.)

- 0.34 mol KClO
- 0.16 mol HCl
- 0.082 mol Ba(OH)₂
- 0.34 mol HCl
- 0.33 mol KCl

**Explanation:**
To form a buffer solution, we need to add a substance that will create a conjugate base or acid pair with hypochlorous acid. This allows the solution to resist changes in pH when strong acids or bases are added.
Transcribed Image Text:**Buffer Solution Formation with Hypochlorous Acid** An aqueous solution contains **0.33 M hypochlorous acid**. One liter of this solution could be converted into a buffer by the addition of: (Assume that the volume remains constant as each substance is added.) - 0.34 mol KClO - 0.16 mol HCl - 0.082 mol Ba(OH)₂ - 0.34 mol HCl - 0.33 mol KCl **Explanation:** To form a buffer solution, we need to add a substance that will create a conjugate base or acid pair with hypochlorous acid. This allows the solution to resist changes in pH when strong acids or bases are added.
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