An analysis of a circuit shown in Fig. P2.1 yields the quadratic equation for the current I as 31² + 61 = 45, where I is in amps. (a) Rewrite the above equation in the form ľ² + al + b = 0, where a and b are constants. (b) Solve the equation in part (a) by each of the following methods: fac- toring, completing the square, and the quadratic formula. Vs R = 39 www I 6 V

Advanced Engineering Mathematics
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ISBN:9780470458365
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An analysis of a circuit shown in Fig.
P2.1 yields the quadratic equation for
the current I as 31² + 61 = 45, where I
is in amps.
(a) Rewrite the above equation in the
form I² + al + b = 0, where a and b
are constants.
(b) Solve the equation in part (a) by
each of the following methods: fac-
toring, completing the square, and
the quadratic formula.
Vs
R = 39
Hilt
-
6 V
Transcribed Image Text:An analysis of a circuit shown in Fig. P2.1 yields the quadratic equation for the current I as 31² + 61 = 45, where I is in amps. (a) Rewrite the above equation in the form I² + al + b = 0, where a and b are constants. (b) Solve the equation in part (a) by each of the following methods: fac- toring, completing the square, and the quadratic formula. Vs R = 39 Hilt - 6 V
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