An analysis of a circuit shown in Fig. P2.1 yields the quadratic equation for the current I as 31² + 61 = 45, where I is in amps. (a) Rewrite the above equation in the form ľ² + al + b = 0, where a and b are constants. (b) Solve the equation in part (a) by each of the following methods: fac- toring, completing the square, and the quadratic formula. Vs R = 39 www I 6 V
An analysis of a circuit shown in Fig. P2.1 yields the quadratic equation for the current I as 31² + 61 = 45, where I is in amps. (a) Rewrite the above equation in the form ľ² + al + b = 0, where a and b are constants. (b) Solve the equation in part (a) by each of the following methods: fac- toring, completing the square, and the quadratic formula. Vs R = 39 www I 6 V
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.3: Quadratic Equations
Problem 81E
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Please solve it with MATLAB.
![An analysis of a circuit shown in Fig.
P2.1 yields the quadratic equation for
the current I as 31² + 61 = 45, where I
is in amps.
(a) Rewrite the above equation in the
form I² + al + b = 0, where a and b
are constants.
(b) Solve the equation in part (a) by
each of the following methods: fac-
toring, completing the square, and
the quadratic formula.
Vs
R = 39
Hilt
-
6 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F23a9413a-421f-4b00-8caa-313f85072403%2F7ef12c70-0ef1-49d1-8f8a-81c73aae4e47%2Fwq7chwn_processed.png&w=3840&q=75)
Transcribed Image Text:An analysis of a circuit shown in Fig.
P2.1 yields the quadratic equation for
the current I as 31² + 61 = 45, where I
is in amps.
(a) Rewrite the above equation in the
form I² + al + b = 0, where a and b
are constants.
(b) Solve the equation in part (a) by
each of the following methods: fac-
toring, completing the square, and
the quadratic formula.
Vs
R = 39
Hilt
-
6 V
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