An alpha particle with kinetic energy 11.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=pob, where po is the magnitude of the initial momentum of the alpha particle and b=1.50x10-12 m. (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.) Part A What is the distance of closest approach? Express your answer in meters.

An alpha particle with kinetic energy 11.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=pob, where po is the magnitude of the initial momentum of the alpha particle and b=1.50x10-12 m. (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.) Part A What is the distance of closest approach? Express your answer in meters.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Rutherford's scattering experiment

Rutherford’s scattering experiment is also known as the gold foil experiment. This experiment disproved the plum pudding model of J.J. Thomson. In a gold foil experiment, high-energy alpha particles are made to strike a thin gold foil. The scattered alpha particles are detected using a detector. This experiment showed that the positive charge of the atom is at the center. Most of the atom’s mass is also confined to a small volume at the center. This region is known as the nucleus of the atom.

Question

An alpha particle with kinetic energy 11.0 MeV
makes a collision with lead nucleus, but it is not
"aimed" at the center of the lead nucleus, and has
an initial nonzero angular momentum (with respect
to the stationary lead nucleus) of magnitude
L=pob, where po is the magnitude of the initial
momentum of the alpha particle and
Part A
What is the distance of closest approach?
m. (Assume that the lead nucleus
Express your answer in meters.
remains stationary and that it may be treated as a
point charge. The atomic number of lead is 82. The
alpha particle is a helium nucleus, with atomic
number 2.)
να ΑΣφ

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