An airplane with a speed of 75.9 m/s is dlimbing upward at an angle of 45.8° with respect to the horizontal. When the plane's altitude is 729 m, the pilot releases a package. (a) Calculate the distance along the ground, measured from a point directly beneath the point of release, to where the package hits the earth. (b) Relative to the ground, determine the angle of the velocity vector of the package just before impact. (a) Number Units (b) Number Units

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Chapter1: Units, Trigonometry. And Vectors
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An airplane with a speed of 75.9 m/s is climbing upward at an angle of 45.8 ° with respect to the horizontal. When the plane's altitude is 729 m, the pilot releases a package. (a) Calculate the distance along the
ground, measured from a point directly beneath the point of release, to where the package hits the earth. (b) Relative to the ground, determine the angle of the velocity vector of the package just before impact.
(a) Number
Units
(b) Number
Units
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Transcribed Image Text:An airplane with a speed of 75.9 m/s is climbing upward at an angle of 45.8 ° with respect to the horizontal. When the plane's altitude is 729 m, the pilot releases a package. (a) Calculate the distance along the ground, measured from a point directly beneath the point of release, to where the package hits the earth. (b) Relative to the ground, determine the angle of the velocity vector of the package just before impact. (a) Number Units (b) Number Units Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER
Expert Solution
Step 1

Speed of airplane (v) = 75.9 msClimbing angle of airplane (θ) = 45.8oAltitude of airplane (h) = 729 m 

 

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