An air-filled parallel plate capacitor is connected to a battery so the difference in potential between the plates is AV and the magnitude of the electric field betweer the plates is E. If the battery is disconnected, and then a dielectric is inserted between the plates O AV remains the same, E increases O AV increases, E increases O AV remains the same, E remains the same O AV decreases, E increases O AV decreases, E decreases O AV remains the same, E decreases O AV decreases, E remains the same O AV increases, E decreases O AV increases, E remains the same

College Physics
11th Edition
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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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**Capacitor Problem: Dielectric Effect on Voltage and Electric Field**

An air-filled parallel plate capacitor is connected to a battery, resulting in a difference in potential (\(\Delta V\)) between the plates and a magnitude of the electric field (\(E\)). When the battery is disconnected, and a dielectric is inserted between the plates, consider the following possibilities:

1. \( \Delta V \) remains the same, \( E \) increases
2. \( \Delta V \) increases, \( E \) increases
3. \( \Delta V \) remains the same, \( E \) remains the same
4. \( \Delta V \) decreases, \( E \) increases
5. \( \Delta V \) decreases, \( E \) decreases
6. \( \Delta V \) remains the same, \( E \) decreases
7. \( \Delta V \) decreases, \( E \) remains the same
8. \( \Delta V \) increases, \( E \) decreases
9. \( \Delta V \) increases, \( E \) remains the same

Each option presents a different scenario regarding how the voltage and electric field might change upon the insertion of the dielectric. This is a conceptual question commonly discussed in the context of capacitors and dielectrics in physics courses.
Transcribed Image Text:**Capacitor Problem: Dielectric Effect on Voltage and Electric Field** An air-filled parallel plate capacitor is connected to a battery, resulting in a difference in potential (\(\Delta V\)) between the plates and a magnitude of the electric field (\(E\)). When the battery is disconnected, and a dielectric is inserted between the plates, consider the following possibilities: 1. \( \Delta V \) remains the same, \( E \) increases 2. \( \Delta V \) increases, \( E \) increases 3. \( \Delta V \) remains the same, \( E \) remains the same 4. \( \Delta V \) decreases, \( E \) increases 5. \( \Delta V \) decreases, \( E \) decreases 6. \( \Delta V \) remains the same, \( E \) decreases 7. \( \Delta V \) decreases, \( E \) remains the same 8. \( \Delta V \) increases, \( E \) decreases 9. \( \Delta V \) increases, \( E \) remains the same Each option presents a different scenario regarding how the voltage and electric field might change upon the insertion of the dielectric. This is a conceptual question commonly discussed in the context of capacitors and dielectrics in physics courses.
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