An air capacitor is made from two flat parallel plates 1.50 mm apart. The magnitude of charge on each plate is 0.0180 μC when the potential difference is 200 V. A) What is the capacitance? Express your answer in farads. B) What is the area of each plate? Express your answer in meters squared. C) What maximum voltage can be applied without dielectric breakdown? (Dielectric breakdown for air occurs at an electric field strength of 3.0×106V/m.) Express your answer in volts. D) When the charge is 0.0180 μC, what total energy is stored? Express your answer in joules.
An air capacitor is made from two flat parallel plates 1.50 mm apart. The magnitude of charge on each plate is 0.0180 μC when the potential difference is 200 V. A) What is the capacitance? Express your answer in farads. B) What is the area of each plate? Express your answer in meters squared. C) What maximum voltage can be applied without dielectric breakdown? (Dielectric breakdown for air occurs at an electric field strength of 3.0×106V/m.) Express your answer in volts. D) When the charge is 0.0180 μC, what total energy is stored? Express your answer in joules.
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An air capacitor is made from two flat parallel plates 1.50 mm apart. The magnitude of charge on each plate is 0.0180 μC when the potential difference is 200 V.
A) What is the capacitance?
Express your answer in farads.
B) What is the area of each plate?
Express your answer in meters squared.
C) What maximum voltage can be applied without dielectric breakdown? (Dielectric breakdown for air occurs at an electric field strength of 3.0×106V/m.)
Express your answer in volts.
D) When the charge is 0.0180 μC, what total energy is stored?
Express your answer in joules.
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