A 7.44 µF isolated capacitor is constructed with Teflon, having a dielectric constant of 2.10, between the plates. The capacitor is initially charged to 1.34 volts, and then the Teflon is removed. After removing the Teflon, what is the potential difference across the capacitor plates?
Dielectric Constant Of Water
Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.
Electrostatic Potential and Capacitance
An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
It is given that, initially the capacitor has a capacitance of , the capacitor having a medium with a dielectric constant of between the plates. Initially, the capacitor is charged to .
It is required to find the potential difference across the plates if the dielectric medium is removed from the capacitor.
It is known that, the charge on a capacitor is calculated as:
Here is the capacitance of the capacitor, and is the voltage across the capacitor.
It is also known that, if a dielectric material of a dielectric constant is removed from a capacitor of capacitance . Then, the new capacitance of the capacitor will be:
Trending now
This is a popular solution!
Step by step
Solved in 2 steps