An agency uses the following formula to determine pavement condition rating, PCR = 99.3 - 5.51 (5.0-ROUGH) - 1.59 LNALL -0.221 AVGOUT -0.0306 LONG - 0.531 TRAN, where we have the following. ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5 LNALL = natural logarithm of alligator cracking, ft per mile AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch LONG = longitudinal cracking, ft per mile TRAN = transverse cracking, number of cracks per mile And, present serviceability rating is determined as the following. PSR = 5e-0.0051118-IRI-0.0016027 A pavement section has the following distress data. IRI = 106 in./mi Alligator cracking = 110 ft/mi Average rutting = 0.20 in. Longitudinal cracks = 130 ft/mi Transverse cracks = 12/mi Determine the current PCR for this section. PCR = Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI value (in in./mi) that will trigger the rehabilitation.
An agency uses the following formula to determine pavement condition rating, PCR = 99.3 - 5.51 (5.0-ROUGH) - 1.59 LNALL -0.221 AVGOUT -0.0306 LONG - 0.531 TRAN, where we have the following. ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5 LNALL = natural logarithm of alligator cracking, ft per mile AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch LONG = longitudinal cracking, ft per mile TRAN = transverse cracking, number of cracks per mile And, present serviceability rating is determined as the following. PSR = 5e-0.0051118-IRI-0.0016027 A pavement section has the following distress data. IRI = 106 in./mi Alligator cracking = 110 ft/mi Average rutting = 0.20 in. Longitudinal cracks = 130 ft/mi Transverse cracks = 12/mi Determine the current PCR for this section. PCR = Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI value (in in./mi) that will trigger the rehabilitation.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![An agency uses the following formula to determine pavement condition rating,
PCR = 99.3 5.51 (5.0-ROUGH) 1.59 LNALL 0.221 AVGOUT 0.0306 LONG
where we have the following.
ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5
LNALL = natural logarithm of alligator cracking, ft per mile
AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch
LONG = longitudinal cracking, ft per mile
TRAN = transverse cracking, number of cracks per mile
And, present serviceability rating is determined as the following.
PSR = 5e-0.0051118 IRI-0.0016027
A pavement section has the following distress data.
IRI = 106 in./mi
Alligator cracking
110 ft/mi
Average rutting =
0.20 in.
Longitudinal cracks = 130 ft/mi
Transverse cracks = 12/mi
Determine the current PCR for this section.
PCR =
0.531 TRAN,
Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI value (in in./mi) that will trigger the
rehabilitation.
in./mi](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b659566-a2ad-4ea7-b4ee-c67667eae8be%2Fccada16f-4765-44e7-8c10-f26d85c094d5%2F0t8vbd_processed.png&w=3840&q=75)
Transcribed Image Text:An agency uses the following formula to determine pavement condition rating,
PCR = 99.3 5.51 (5.0-ROUGH) 1.59 LNALL 0.221 AVGOUT 0.0306 LONG
where we have the following.
ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5
LNALL = natural logarithm of alligator cracking, ft per mile
AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch
LONG = longitudinal cracking, ft per mile
TRAN = transverse cracking, number of cracks per mile
And, present serviceability rating is determined as the following.
PSR = 5e-0.0051118 IRI-0.0016027
A pavement section has the following distress data.
IRI = 106 in./mi
Alligator cracking
110 ft/mi
Average rutting =
0.20 in.
Longitudinal cracks = 130 ft/mi
Transverse cracks = 12/mi
Determine the current PCR for this section.
PCR =
0.531 TRAN,
Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI value (in in./mi) that will trigger the
rehabilitation.
in./mi
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