An African elephant is walking along when a mini-black hole suddenly appears directly above him. The mass of the black hole is so great that its gravity is able to lift the elephant from the Earth. How close must the mini-black hole be to the elephant's center of mass in order to just overcome the downward pull of Earth's gravity? (Treat the mass of the elephant as if it's concentrated at the elephant's center. Mass of Earth MẸ = 6.97 x 1024 kg Mass of mini-black hole MBH = 4.17 x 1012 kg Radius of Earth RE Mass of elephant (not needed) = 6.40 x 106 meters

An African elephant is walking along when a mini-black hole suddenly appears directly above him. The mass of the black hole is so great that its gravity is able to lift the elephant from the Earth. How close must the mini-black hole be to the elephant's center of mass in order to just overcome the downward pull of Earth's gravity? (Treat the mass of the elephant as if it's concentrated at the elephant's center. Mass of Earth MẸ = 6.97 x 1024 kg Mass of mini-black hole MBH = 4.17 x 1012 kg Radius of Earth RE Mass of elephant (not needed) = 6.40 x 106 meters

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

If you weigh 665 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 15.0 km? 1.99x1030 kg, the gravitational constant to be G 6.67x101 N m2/kg2 , and the acceleration due to gravity Take the mass of the sun to be ms at the earth's surface to be g 9.810 m/s2 .
If you weigh 685 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 18.0 km ? Take the mass of the sun to be ms = 1.99×1030 kg , the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , and the acceleration due to gravity at the earth's surface to be g = 9.810 m/s2 . Express your weight wstar in newtons.
Problem 7. Use Kepler's third law (and the reduced mass) to derive the time it will take two baseballs, initially at rest a meter apart in deep space, to hit each other due to gravitational attraction. The mass of a baseball is 145 grams. Ignore the diameter of the baseballs; i.e. assume they are point particles.
If the Sun were to collapse into a black hole, the point of no return for an investigator would be approximately 3 km from the center singularity. Would the investigator be able to survive visiting even 876 km from the center? Answer this by finding the difference in the gravitational attraction (in N) the black hole exerts on a 1.0 kg mass at the head and at the feet of the investigator. (Assume the investigator is about 2 m tall and is oriented radially with respect to the black hole. Enter the magnitude.)
The Oort Cloud extends out to (possibly) one light-year from the sun. Objects in the Oort Cloud are still gravitationally bound to the sun. Suppose one such iceball orbits the sun in a circle. I'm going to alter some numbers, such as the mass of the sun and even G. The gravitational force is directed toward the sun and has the following magnitude: Calculate the force on the object if these are the numbers: G = 6.1*10-11 N*m2/kg2 M = 2.7*1030 kg m = 1.5*108 kg r = 19*1015 m Calculate your answer in microNewtons (10-6 N).
Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is v| = 225 km/s and the orbital period of each is 11.6 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 x 1030 kg.) M XCM M Part 1 of 3 - Conceptualize From the given data, it is difficult to estimate a reasonable answer to this problem without working through the details and actually solving it. A reasonable guess might be that each star has a mass equal to or slightly larger than our Sun because fourteen days is short compared to the periods of all the Sun's planets. Part 2 of 3 - Categorize The only force acting on each star is the central gravitational force of attraction which results in a centripetal acceleration. When we solve Newton's second law, we can find the unknown mass in terms of the variables…
Let's say we have a M1 and M2. Let's just say. Let's examine this hypothetical situation. The first mass would be 1.50 kg and the second mass would be 2.00 kg. These two masses would then be separated by a length or we should say a distance of this L = 2.50 m. Let's say we want to place a third mass (immaterial mass) in the middle of the two masses, such that there would be no net force. Find this specific place where this would occur, and to make it easy, find the distance from the first mass towards this third mass
Two objects, m1 and m2 are gravitationally attracted to one another. However, m1 is 500 times more massive than m2. Which mass experiences the greater gravitational attractive pull force? A) mass m1 experiences a greater attractive force from m2 B) mass m2 experiences a greater attractive force from m1 C) both masses experience equal but opposite attractive forces D) the problem statement does not provide enough information to be solved
Assuming a circular orbit for the Sun about the center of the Milky Way galaxy, calculate its orbital speed using the following information: The mass of the galaxy is equivalent to a single mass 1.5×1011 times that of the Sun (or3×1041 kg ), located 30,000 ly away.
(Astronomy) Black Hole Gravity II. If a person was falling feet first into a 10-solar-mass black hole and his feet were at the Schwarzschild radius, what is the gravitational acceleration at his head? Assume the person is 2 m tall. Express your answer in units of m/s2. Assume gravitational acceleration is g=GM/r^2
The Schwarzschild radius is a distance from a black hole where the escape velocity equals the speed of light (even light cannot escape from a black hole). Determine the Schwarzschild radius for a black hole with the mass of the Sun.
Black Hole Gravity III. If a person is falling feet first into a black hole, her feet are at the Schwarzschild radius, and her head is outside the radius by an additional 2 m, what is the approximate ratio of the gravitational acceleration felt at her feet compared to the gravitational acceleration felt at her head? Would she be stretched and squished differently at her head and feet? Assume the gravitational acceleration is g = GM⁄r2.