An adventurer builds a 1.80 m3 raft made out of cherry wood (PCHERRY = 800 kg/m³) and places it in the seawater (PSEAWATER = 1030 kg/m³). Determine the volume of the Styrofoam (PSTYROFOAM = 32.0 kg/m³) that would have to be attached to the bottom of the raft so only half of the raft's volume is submerged in the water. O 0.498 m3 O 0.721 m3 O 0.699 m O 0.514 m3 O 0.0072 m3

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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An adventurer builds a 1.80 m3 raft made out of cherry wood (PCHERRY = 800 kg/m³) and places it in the seawater (PSEAWATER = 1030 kg/m³). Determine the volume of the Styrofoam
(PSTYROFOAM = 32.0 kg/m³) that would have to be attached to the bottom of the raft so only half of the raft's volume is submerged in the water.
O 0.498 m3
O 0.721 m3
O 0.699 m3
O 0.514 m3
O 0.0072 m3
Transcribed Image Text:An adventurer builds a 1.80 m3 raft made out of cherry wood (PCHERRY = 800 kg/m³) and places it in the seawater (PSEAWATER = 1030 kg/m³). Determine the volume of the Styrofoam (PSTYROFOAM = 32.0 kg/m³) that would have to be attached to the bottom of the raft so only half of the raft's volume is submerged in the water. O 0.498 m3 O 0.721 m3 O 0.699 m3 O 0.514 m3 O 0.0072 m3
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