A paperweight, when weighed in air, has a weight of W = 4.65 N. When completely immersed in water, however, it has a weight of Win water = 3.43 N. Find the volume of the paperweight.

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**Educational Content: Buoyancy and Volume Calculation**

A paperweight, when weighed in air, has a weight of \( W = 4.65 \, \text{N} \). When completely immersed in water, however, it has a weight of \( W_{\text{in water}} = 3.43 \, \text{N} \). Find the volume of the paperweight.

---

**Instructions:**

Enter the calculated volume in the provided space, followed by the appropriate units.

**Concepts Involved:**

- *Buoyant Force:* The difference in weight in air and in water is due to the buoyant force exerted by water.
- *Archimedes' Principle:* This principle helps determine that the buoyant force is equal to the weight of the liquid displaced by the object.
- *Volume Calculation:* Use Archimedes' principle to find the volume of the object based on the change in weight.

**Formulas to Consider:**

- \( F_{\text{buoyant}} = W - W_{\text{in water}} \)
- \( F_{\text{buoyant}} = \rho_{\text{water}} \times V \times g \)

Where:
- \( F_{\text{buoyant}} \) is the buoyant force,
- \( \rho_{\text{water}} \) is the density of water (approximately \( 1000 \, \text{kg/m}^3 \)),
- \( V \) is the volume of the object,
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)).

**Calculate the Volume:**

Rearrange the formula to solve for \( V \):

\[
V = \frac{F_{\text{buoyant}}}{\rho_{\text{water}} \times g}
\]

**Submit your answer in the box provided:**

- Number: [Text Box]
- Units: [Dropdown for Units]

--- 

Make sure you understand the underlying principles of buoyancy and volume calculation for success in solving similar problems.
Transcribed Image Text:**Educational Content: Buoyancy and Volume Calculation** A paperweight, when weighed in air, has a weight of \( W = 4.65 \, \text{N} \). When completely immersed in water, however, it has a weight of \( W_{\text{in water}} = 3.43 \, \text{N} \). Find the volume of the paperweight. --- **Instructions:** Enter the calculated volume in the provided space, followed by the appropriate units. **Concepts Involved:** - *Buoyant Force:* The difference in weight in air and in water is due to the buoyant force exerted by water. - *Archimedes' Principle:* This principle helps determine that the buoyant force is equal to the weight of the liquid displaced by the object. - *Volume Calculation:* Use Archimedes' principle to find the volume of the object based on the change in weight. **Formulas to Consider:** - \( F_{\text{buoyant}} = W - W_{\text{in water}} \) - \( F_{\text{buoyant}} = \rho_{\text{water}} \times V \times g \) Where: - \( F_{\text{buoyant}} \) is the buoyant force, - \( \rho_{\text{water}} \) is the density of water (approximately \( 1000 \, \text{kg/m}^3 \)), - \( V \) is the volume of the object, - \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)). **Calculate the Volume:** Rearrange the formula to solve for \( V \): \[ V = \frac{F_{\text{buoyant}}}{\rho_{\text{water}} \times g} \] **Submit your answer in the box provided:** - Number: [Text Box] - Units: [Dropdown for Units] --- Make sure you understand the underlying principles of buoyancy and volume calculation for success in solving similar problems.
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