An activated sludge tank is 30 m long and 10 m wide and has an SWD of 4 m. The wastewater flow is 4.0 ML/day and! Compute: a) the BOD concentration which will be applied to the aeration tank b) the food-to-microorganism ratio for the system. O a) 105 mg/L b) F/M=0.35 O a) 195 mg/L b) F/M=0.65 O a) 105 mg/L b) F/M=0.22 O a) 195 mg/L b) F/M=0.35 I the raw 5-day BOD is 300 mg/L. Assuming that 35 percent of the raw BOD is removed in the primary clarifier, and the MLSS concentration is 1000 mg/l (

An activated sludge tank is 30 m long and 10 m wide and has an SWD of 4 m. The wastewater flow is 4.0 ML/day and! Compute: a) the BOD concentration which will be applied to the aeration tank b) the food-to-microorganism ratio for the system. O a) 105 mg/L b) F/M=0.35 O a) 195 mg/L b) F/M=0.65 O a) 105 mg/L b) F/M=0.22 O a) 195 mg/L b) F/M=0.35 I the raw 5-day BOD is 300 mg/L. Assuming that 35 percent of the raw BOD is removed in the primary clarifier, and the MLSS concentration is 1000 mg/l (

Structural Analysis

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ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

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Problem 1P

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Integrated Solid Waste Management

Integrated Solid Waste Management (ISWM) is a thorough waste suppression, compost, removal and recycling Program. An effective ISWM system considers how to suppress, manage and recycle solid waste in a manner that is most efficiently to protect human health and the surrounding. ISWM system requires evaluation of public wants and demands and then selecting and merging the most effective waste management activities for the proposed demands. The main ISWM activities for solid waste management are Waste prevention, Recycling and Composting, and Combustion and Removal and waste collection in a properly planned, constructed, managed and mitigated landfill areas. Each of these requires careful designing, financing, accumulation, and delivery of activities.

Question

An activated sludge tank is 30 m long and 10 m wide and has an SWD of 4 m. The wastewater flow is 4.0 ML/day and
Compute:
a) the BOD concentration which will be applied to the aeration tank
b) the food-to-microorganism ratio for the system.
O a) 105 mg/L
b) F/M=0.35
O a) 195 mg/L
b) F/M=0.65
O a) 105 mg/L
b) F/M=0.22
O a) 195 mg/L
b) F/M=0.35
the raw 5-day BOD is 300 mg/L. Assuming that 35 percent of the raw BOD is removed in the primary clarifier, and the MLSS concentration is 1000 mg/L.

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