An accounting office has 6 incoming telephone lines. The probability distribution of the number of busy lines, X, is as follows: 1 2 4 Total P(X = x;) 0.05 0.12 0.17 0.31 0.19 0.15 0.01 1 1. Use the random variable notation to express symbolically each of the following: An event in which the number of busy lines is exactly 4. The probability of an event in which the number of busy lines is exactly 1. The probability of an event in which the number of busy lines is exactly 4 is equal to 0.19. 2. Use the above probability distribution table to find the following: a. P(1 < X < 3) = (Round the answer to 2 decimals) %3D b. P(0 < X < 3) = c. P(X < 5) = (Round the answer to 2 decimals) %3D (Round the answer to 2 decimals)

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4.1.4

An accounting office has 6 incoming telephone lines. The probability distribution of the number of busy
lines, X, is as follows:
1
2
3
4
5
Total
P(X = x;)
0.05
0.12
0.17
0.31
0.19
0.15
0.01
1
1. Use the random variable notation to express symbolically each of the following:
V An event in which the number of busy lines is exactly 4.
v The probability of an event in which the number of busy lines is exactly 1.
The probability of an event in which the number of busy lines is exactly 4
is equal to 0.19.
2. Use the above probability distribution table to find the following:
а. Р(1 < X < 3) -
(Round the answer to 2 decimals)
b. P(0 < X < 3) =
(Round the answer to 2 decimals)
с. Р(X < 5) %3
(Round the answer to 2 decimals)
Transcribed Image Text:An accounting office has 6 incoming telephone lines. The probability distribution of the number of busy lines, X, is as follows: 1 2 3 4 5 Total P(X = x;) 0.05 0.12 0.17 0.31 0.19 0.15 0.01 1 1. Use the random variable notation to express symbolically each of the following: V An event in which the number of busy lines is exactly 4. v The probability of an event in which the number of busy lines is exactly 1. The probability of an event in which the number of busy lines is exactly 4 is equal to 0.19. 2. Use the above probability distribution table to find the following: а. Р(1 < X < 3) - (Round the answer to 2 decimals) b. P(0 < X < 3) = (Round the answer to 2 decimals) с. Р(X < 5) %3 (Round the answer to 2 decimals)
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