An AC power Supply is connected to a Capacitor of capacitance 5.5.10-6 F. At time t=0, the power supply is switched on and storts providing a time-dependent voltage VCE) = Vo cos (we) across the capacitor, where Vo = 5.5 V and w= 373 rad. The Capacitor is initially uncharged. Find the Current, in milliamperes, through the capacitor at t=2.5s

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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**Problem Statement:**

An AC power supply is connected to a capacitor with a capacitance of \(5.5 \times 10^{-6} \, \text{F}\). At time \(t = 0\), the power supply is switched on and starts providing a time-dependent voltage \(V(t) = V_0 \cos(\omega t)\) across the capacitor, where \(V_0 = 5.5 \, \text{V}\) and \(\omega = 373 \, \text{rad/s}\). The capacitor is initially uncharged.

**Task:**

Find the current, in milliamperes, through the capacitor at \(t = 2.5 \, \text{s}\).
Transcribed Image Text:**Problem Statement:** An AC power supply is connected to a capacitor with a capacitance of \(5.5 \times 10^{-6} \, \text{F}\). At time \(t = 0\), the power supply is switched on and starts providing a time-dependent voltage \(V(t) = V_0 \cos(\omega t)\) across the capacitor, where \(V_0 = 5.5 \, \text{V}\) and \(\omega = 373 \, \text{rad/s}\). The capacitor is initially uncharged. **Task:** Find the current, in milliamperes, through the capacitor at \(t = 2.5 \, \text{s}\).
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