An 800 kg boulder is raised from a quarry 183 m deep by a long, uniform chain having a mass of 560 kg. This chain is of uniform strength, but at any point it can support a maximum tension no greater than 2.50 times its weight without breaking. What is the maximum acceleration the boulder can have and still get out of the quarry?
An 800 kg boulder is raised from a quarry 183 m deep by a long, uniform chain having a mass of 560 kg. This chain is of uniform strength, but at any point it can support a maximum tension no greater than 2.50 times its weight without breaking. What is the maximum acceleration the boulder can have and still get out of the quarry?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:**Problem Statement:**
An 800 kg boulder is raised from a quarry 183 m deep by a long, uniform chain having a mass of 560 kg. This chain is of uniform strength, but at any point, it can support a maximum tension no greater than 2.50 times its weight without breaking.
*What is the maximum acceleration the boulder can have and still get out of the quarry?*
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**Solution Outline:**
To solve this problem, we need to calculate the maximum acceleration the boulder can have without exceeding the tension limit of the chain.
We will utilize the following steps:
1. **Calculate the weight of the boulder and the chain:**
- Weight of the boulder, \( W_{\text{boulder}} = m_{\text{boulder}} \cdot g \)
- Weight of the chain, \( W_{\text{chain}} = m_{\text{chain}} \cdot g \)
2. **Determine the maximum tension the chain can support:**
- Maximum tension, \( T_{\text{max}} = 2.50 \times W_{\text{chain}} \)
3. **Set up the forces acting on the boulder when it is being lifted:**
- The chain needs to support both the weight of the boulder and the chain itself. Therefore, the total weight the chain needs to lift is the sum of the weight of the boulder and half the weight of the chain (since the other half is tackled by the part of the chain still laying on the ground).
4. **Use Newton's Second Law to express the forces acting on the boulder and solving for the maximum acceleration:**
- The net force acting on the boulder will be the difference between the maximum tension and the combined weight of the boulder and the chain segment being lifted.
- From \( F_{\text{net}} = m_{\text{total}} \cdot a \), solve for \( a \).
By following these outlined steps, we will obtain the maximum acceleration that the boulder can have without causing the chain to break while being lifted out of the quarry.
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This solution approach encapsulates the principles of physics and mechanical engineering, specifically related to the concepts of weight, tension, and acceleration under the influence of gravity, ensuring a clear conceptual understanding for the students.
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