An 8.0µC point charge is tied to a 6.25µC point charge by a light 3.0cm long nonconducting string. The 8.0µC point charge is glued in place. The charges are resting on a horizontal frictionless table. 8.0uc 6.25 uc ... 3.0cm .. What is the magnitude ( in units of N) of the tension in the string? (Example: If your answer is 55.4 N, enter your answer as 55.4 in the answer box).

An 8.0µC point charge is tied to a 6.25µC point charge by a light 3.0cm long nonconducting string. The 8.0µC point charge is glued in place. The charges are resting on a horizontal frictionless table. 8.0uc 6.25 uc ... 3.0cm .. What is the magnitude ( in units of N) of the tension in the string? (Example: If your answer is 55.4 N, enter your answer as 55.4 in the answer box).

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A point charge, q = -5.0 nC, and m = 2.0 x 10-18 kg, is shot vertically upward with an initial speed of 3.0 x 105 m/s from a thin, infinite, planar sheet of uniform charge with surface charge density of σ = +4.0 . To what vertical elevation will q rise above the sheet of charge? Neglect gravity. a. 6.0 cm b. 8.0 cm c. 5.0 cm d. 4.0 cm e. 7.0 cm
Consider the following. B 0.500 mm 60.0° (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 6.60 pC, and C = -4.40 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? magnitude N/C direction ° counterclockwise from the +x axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? O The magnitude of the field would be doubled. O The field would be unchanged. O The magnitude of the field would be halved. O The magnitude of the field would be quadrupled.
1.A charge Q, is at point M, 16 M,= -12 M₂ = 20, and a charge Q, is at N(-18, 3, 7) in free space. If distances are given in cm,solve for: A. RMN B. RMN C. Determine the vector force exerted on Q by Q₁, if the permittivity of free space is equal to 10°/36TT. If the charges are -25μC and 40μC respectively.
Н. W. 1. How much work is done to assemble eight identical point charges, each of magnitude q, at the corners of a cube of side a? 2. Three charges with q= 3x10 C and q= 6x10° C are placed on the x-axis, as shown in the figure. The distance between g and gi is a = 0.600 m. a a (a) What is the net force exerted on q by the other two charges q1? (b) What is the electric field at the origin due to the two charges q1? (c) What is the electric potential at the origin due to the two charges q1?
Two identical metal spheres A and B are connected by a plastic rod. Both are initially neutral. 2.0×1012 electrons are added to sphere A, then the connecting rod is removed. A)Afterward, what is the charge of A?B)Afterward, what is the charge of B?
Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The oxygen-hydrogen distance is 0.096 nm. 104.5" 0.096 nm T: Considering the atoms as non-bonded, independent charges... what is the net electric force vector on the oxygen atom (blue)? insidering the atoms as non-bonded, independent charges... what is the potential energy of this arrangement? Iculate the electric dipole moment (i.e. dipole vector) of the water molecule, using the axes in the figure to establish unit vectors. Hint: Treat the molecule as two independent dipoles, and add the moments as vectors. I claim it is p = -1.88 x 10-299 Cm. Am I correct? Why is it negative? (NOTE: The measured value of the dipole moment of water is about [p] = 0.617 x 10-29 C m, or about 1/3 of our calculated value.
A factory is spray-painting large sheets of metal electrostatically. The sheets have dimensions of 2.4 m by 2.4 m and are charged with 0.82 mC. A 10 kg drum of paint is charged with -89 μCμC, and the spray nozzle produces uniform droplets of 2.4 g. Assume that all charge is distributed uniformly on the sheet and in the paint and no charge is lost during the spraying process. Determine the magnitude of acceleration the paint droplets feel due to the metal sheet. Give your answer in units of ms2ms2.
5. In below figure, a small, non-conductor ball of mass m =3.0 mg and charge q = 9.0 µC hangs from an insulating thread that makes an angle e charged non- conductor plane. Considering the gravitational force on the ball and assuming the plane extends far vertically and into and out of the page, calculate the area charge density of the plane. Length of string is 120.0 cm. 30° with a vertical, uniformly lo120cm + Jplone
For all following sections, assume |2|= 1 |p|= 5, R₁ = 5 mm, R₁ = 15 mm, and R₂ = 2 cm.
Consider the following. 60.0⁰ B 0.500 mm (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 7.10 pC, and C= -4.30 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 C.) magnitude N/C direction o counterclockwise from the +x-axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? O The field would be unchanged. O The magnitude of the field would be doubled. O The magnitude of the field would be quadrupled. O The magnitude of the field would be halved.
You have a vertical polyethylene rod. It is 30 cm. It Carries a negative charge Q=-3μC which is distributed uniformly allong it's length. A 51 gram marble of glass Carriies a positive q= +0.44 μC charge . The marble hangs from the rod from a plastic string, 10 cm below the rod. What is the tension in the string?. a. 0.8N b. 0.5N c.0.3N d. 0.2N e. 0N
A wire has a linear charge density (x) = 2.35x, where x is in meters (m) and is in C/m. If the length of the wire is 3.7 m, the total charge on the wire is O 16 C. 11 C. O 8.0 C. 1.2 C.