An 8.00 kg box sits on a ramp that is inclined at 33.0° above thehorizontal. The coefficient of kinetic friction between the box andthe surface of the ramp is = 0.300. A constant horizontal forceF=28.0 N is applied to the box (Figure 1), and the box movesdown the ramp.▼Part AIf the box is initially at rest, what is its speed 2.00 s after the force is applied?Express your answer with the appropriate units.FigureF33.0°HAv =ValueUnitsSubmitRequest Answer1 of 1Provide Feedback

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Answered: An 8.00 kg box sits on a ramp that is…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A box with a mass of 5 kg is moving down the inclined plane at a constant speed of 6 m/s. The coefficient of friction between the box and the surface of the incline is us = 0.25 and µ = 0.15. At the bottom of the incline, a spring is present to stop the box. The spring constant is k = 4 N/mm. What is the maximum force in the spring after the box hits it? 5 kg, 6 m/s m- 35⁰ 400000
u = 0.75 m = 300 kg teta = 27 degrees
A BLOCK IS RESTING ON THE INCLINED SURFACE AS SHOWN WHOSE AXES ARE ORIENTED PARALLEL AND PERPENDICULAR TO THE INCLINED SURFACE. DETERMINE THE RESULTANT FORCE ACTING ALONG THE INCLINED SURFACE. DETERMINE THE TOTAL RESULTANT FORCE ACTING ON THE BODY. DETERMINE THE DIRECTION OF THE RESULTANT WITH RESPECT TO X-AXIS. P = 1,200 lb F = 400 lb 8 = 37⁰
The wheel loads on a jeep are given in the figure shown. Determine the distance x so that the reaction of the beam at B is twice as great as the reaction at A. 600 lb 200 lb 4' B. 15'
A block with mass (m = 19.5 kg) is pulled with a force (F = 280 N) 0 = 25°. a) Draw a free-body diagram. b) Find the normal force. c) If coefficient of friction between the crate and the surface is uz=0.12, what is the value of the frictional force, fr. d) Find the acceleration. e) What minimum horizontal force is needed to move the block with a constant speed (while keeping the F = 280 N)? F m
Problem 1.: In Figure, two blocks are connected by a solid strut attached to each block with frictionless pins. If the coeeficient of friction under each block is 0.25 and B weighs 2700 N, Find the minimum weight of A to prevent motion.
I need the answer as soon as possible
The crate, which has a mass of 100 kg, is subjected to the action of the two forces (Figure 1). If it is originally at rest, determine the distance it slides in order to attain a speed of 6 m/s. The coefficient of kinetic friction between the crate and the surface is uk = 0.2. Mk 800 N 30°/ Figure 1 1000 N 3
The three identical bars, each weighing 6.1 lb, are connected by the two freely pinned links of negligible weight and are resting on a smooth horizontal surface. Calculate the initial acceleration a of the center of the middle bar when the 5.7-lb force is applied to the connecting link as shown. # Answer: a = i 5.7 lb ft/sec²
Problem 2 Determine the force P required to lift the M-kg steel crate which rests against a 5° - wedge on a side and brick wall on the other side. The coefficient of frictions between the crate and wedge, wedge and surface, crate and surface are 0.45, 0.35, and 0.38, respectively. Use the following values, M= 90 kg, and g = 9.806 m/s? Зт 19° 1.2m 21°
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A 130-lb cabinet is mounted on casters that can be locked to prevent their rotation. The coefficient of static friction between the floor and each caster is 0.30. Consider h = 32 in. 24 in. Determine the magnitude of the force P required to move the cabinet to the right if the casters at B are locked and the casters at A are free to rotate. (You must provide an answer before moving to the next part) If the casters at B are locked and the casters at A are free to rotate, the magnitude of the force required to move the cabinet to the right is Ib+
Question A mild steel bar, circular in cross-section, tapers from 40 mm diameter to 20 mm diameter over its length of 800 mm. It is subjected to an axial pull of 20 kN. E = 2 x 105 N/mm². The increase in the length of the rod will be

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