An 61-kg jogger is heading due east at a speed of 3.4 m/s. A 83-kg jogger is heading 52 ° north of east at a speed of 3.3 m/s. Find (a) the magnitude and (b) the direction of the sum of the momenta of the two joggers. Describe the direction as an angle with respect to due east. North East (a) Number i Units (b) Number i Units
An 61-kg jogger is heading due east at a speed of 3.4 m/s. A 83-kg jogger is heading 52 ° north of east at a speed of 3.3 m/s. Find (a) the magnitude and (b) the direction of the sum of the momenta of the two joggers. Describe the direction as an angle with respect to due east. North East (a) Number i Units (b) Number i Units
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An 61-kg jogger is heading due east at a speed of 3.4 m/s. A 83-kg jogger is heading 52 ° north of east at a speed of 3.3 m/s. Find (a) the magnitude and (b) the direction of the sum of the momenta of the two joggers. Describe the direction as an angle with respect to due east.
![An \( 61 \, \text{kg} \) jogger is heading due east at a speed of \( 3.4 \, \text{m/s} \). A \( 83 \, \text{kg} \) jogger is heading \( 52^\circ \) north of east at a speed of \( 3.3 \, \text{m/s} \). Find (a) the magnitude and (b) the direction of the sum of the momenta of the two joggers. Describe the direction as an angle with respect to due east.
**Diagram Explanation:**
- The diagram shows two joggers:
- The first jogger is moving toward the east with a velocity vector \( \vec{v_1} \).
- The second jogger is moving at an angle \( \theta = 52^\circ \) north of east with a velocity vector \( \vec{v_2} \).
The diagram includes directional arrows:
- North is indicated by an upward arrow.
- East is indicated by a rightward arrow.
- The angle \( \theta \) is marked between the horizontal dashed line (due east) and the direction of \( \vec{v_2} \).
**Input Fields:**
(a) Magnitude:
- Number: [Input box]
- Units: [Dropdown menu for unit selection]
(b) Direction:
- Number: [Input box]
- Units: [Dropdown menu for unit selection, possibly for angle units such as degrees]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcae2b0ea-fb22-4919-b71b-a816e853f242%2Fdefd503d-f8c4-4ac4-8a74-51c042eb2a3d%2F3id36xh_processed.png&w=3840&q=75)
Transcribed Image Text:An \( 61 \, \text{kg} \) jogger is heading due east at a speed of \( 3.4 \, \text{m/s} \). A \( 83 \, \text{kg} \) jogger is heading \( 52^\circ \) north of east at a speed of \( 3.3 \, \text{m/s} \). Find (a) the magnitude and (b) the direction of the sum of the momenta of the two joggers. Describe the direction as an angle with respect to due east.
**Diagram Explanation:**
- The diagram shows two joggers:
- The first jogger is moving toward the east with a velocity vector \( \vec{v_1} \).
- The second jogger is moving at an angle \( \theta = 52^\circ \) north of east with a velocity vector \( \vec{v_2} \).
The diagram includes directional arrows:
- North is indicated by an upward arrow.
- East is indicated by a rightward arrow.
- The angle \( \theta \) is marked between the horizontal dashed line (due east) and the direction of \( \vec{v_2} \).
**Input Fields:**
(a) Magnitude:
- Number: [Input box]
- Units: [Dropdown menu for unit selection]
(b) Direction:
- Number: [Input box]
- Units: [Dropdown menu for unit selection, possibly for angle units such as degrees]
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