As shown in the figure, a metal ball with mass m, is initially at rest on a horizontal, frictionless table. A second metal ball with mass m, moving with a speed 2.00 m/s, collides with m,. Assume m, moves initially along the +x-axis. After the collision, m, moves with speed 1.00 m/s at an angle of e = 48.0° to the positive x-axis. (Assume m, = 0.200 kg and m, = 0.300 kg.) After the collision y sin e Before the collision Vy cos e ey sin ø Show hidden (a) Determine the speed (in m/s) of the 0.300 kg ball after the collision. m/s (b) Find the fraction of kinetic energy transferred away or transformed to other forms of energy in the collision. JAK| K;
As shown in the figure, a metal ball with mass m, is initially at rest on a horizontal, frictionless table. A second metal ball with mass m, moving with a speed 2.00 m/s, collides with m,. Assume m, moves initially along the +x-axis. After the collision, m, moves with speed 1.00 m/s at an angle of e = 48.0° to the positive x-axis. (Assume m, = 0.200 kg and m, = 0.300 kg.) After the collision y sin e Before the collision Vy cos e ey sin ø Show hidden (a) Determine the speed (in m/s) of the 0.300 kg ball after the collision. m/s (b) Find the fraction of kinetic energy transferred away or transformed to other forms of energy in the collision. JAK| K;
Related questions
Question
![As shown in the figure, a metal ball with mass \( m_2 \) is initially at rest on a horizontal, frictionless table. A second metal ball with mass \( m_1 \), moving with a speed of 2.00 m/s, collides with \( m_2 \). Assume \( m_1 \) moves initially along the +x-axis. After the collision, \( m_1 \) moves with speed 1.00 m/s at an angle of \( \theta = 48.0^\circ \) to the positive x-axis. (Assume \( m_1 = 0.200 \, \text{kg} \) and \( m_2 = 0.300 \, \text{kg} \).)
**Diagrams:**
- **Before the collision:**
- \( m_1 \) (blue ball) is moving towards \( m_2 \) (orange ball) along the positive x-axis with initial velocity \( \vec{v}_{1i} \).
- **After the collision:**
- \( m_1 \) moves at an angle \( \theta = 48.0^\circ \) with final velocity \( \vec{v}_{1f} \) and its components: \( v_{1f} \sin \theta \) (vertical) and \( v_{1f} \cos \theta \) (horizontal).
- \( m_2 \) moves with final velocity \( \vec{v}_{2f} \) at an angle \( \phi \), having components: \( v_{2f} \sin \phi \) (vertical) and \( v_{2f} \cos \phi \) (horizontal).
**Tasks:**
(a) Determine the speed (in m/s) of the 0.300 kg ball after the collision.
\[
\boxed{\text{Input answer here}}
\]
(b) Find the fraction of kinetic energy transferred away or transformed to other forms of energy in the collision.
\[
\frac{|\Delta K|}{K_i} = \boxed{\text{Input answer here}}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7f2c3d99-9ef7-4143-b412-4ae4e3b56b6f%2F4de2e809-93b4-49f0-8149-33bf69912c30%2Fdtm30hs_processed.png&w=3840&q=75)
Transcribed Image Text:As shown in the figure, a metal ball with mass \( m_2 \) is initially at rest on a horizontal, frictionless table. A second metal ball with mass \( m_1 \), moving with a speed of 2.00 m/s, collides with \( m_2 \). Assume \( m_1 \) moves initially along the +x-axis. After the collision, \( m_1 \) moves with speed 1.00 m/s at an angle of \( \theta = 48.0^\circ \) to the positive x-axis. (Assume \( m_1 = 0.200 \, \text{kg} \) and \( m_2 = 0.300 \, \text{kg} \).)
**Diagrams:**
- **Before the collision:**
- \( m_1 \) (blue ball) is moving towards \( m_2 \) (orange ball) along the positive x-axis with initial velocity \( \vec{v}_{1i} \).
- **After the collision:**
- \( m_1 \) moves at an angle \( \theta = 48.0^\circ \) with final velocity \( \vec{v}_{1f} \) and its components: \( v_{1f} \sin \theta \) (vertical) and \( v_{1f} \cos \theta \) (horizontal).
- \( m_2 \) moves with final velocity \( \vec{v}_{2f} \) at an angle \( \phi \), having components: \( v_{2f} \sin \phi \) (vertical) and \( v_{2f} \cos \phi \) (horizontal).
**Tasks:**
(a) Determine the speed (in m/s) of the 0.300 kg ball after the collision.
\[
\boxed{\text{Input answer here}}
\]
(b) Find the fraction of kinetic energy transferred away or transformed to other forms of energy in the collision.
\[
\frac{|\Delta K|}{K_i} = \boxed{\text{Input answer here}}
\]
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 19 images
