Amplifier's Frequency Response Vcc=20V R1 = 40 kohm R2 = 10 kohm Rc = 4 kohm RE=2 kohm Rs = 1 kohm RL = 2.2 kohm Cs = 10 uF Cc=1 uF CE=20 uF Cbc = 4 pF Cbe = 36 pF Cce 1 pF Cwi=6 pF Cwo = 8 pF Beta = 100 + I Rs V₂ 2 Cs + R₁ Vcc V₁ R₂ Cw₁ C. d. Cbc Rc Che RE Calculate the ac emitter resistance, re. a. 15.762 b. 17.52 23 Ω 26 Q Cc Cce CE CWo ●●● RL
Amplifier's Frequency Response Vcc=20V R1 = 40 kohm R2 = 10 kohm Rc = 4 kohm RE=2 kohm Rs = 1 kohm RL = 2.2 kohm Cs = 10 uF Cc=1 uF CE=20 uF Cbc = 4 pF Cbe = 36 pF Cce 1 pF Cwi=6 pF Cwo = 8 pF Beta = 100 + I Rs V₂ 2 Cs + R₁ Vcc V₁ R₂ Cw₁ C. d. Cbc Rc Che RE Calculate the ac emitter resistance, re. a. 15.762 b. 17.52 23 Ω 26 Q Cc Cce CE CWo ●●● RL
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AMPLIFIER'S FREQUENCY RESPONSE 13
![Amplifier's Frequency Response
Vcc=20V
R1 = 40 kohm
R2 = 10 kohm
Rc = 4 kohm
RE=2 kohm
Rs = 1 kohm
RL = 2.2 kohm
Cs = 10 uF
Cc=1 uF
CE=20 uF
Cbc = 4 pF
Cbe = 36 pF
Cce 1 pF
Cwi=6 pF
Cwo = 8 pF
Beta = 100
+ I
Rs
V₂
2
Cs
+
R₁
Vcc
V₁ R₂ Cw₁
C.
d.
Cbc
Rc
Che
RE
Calculate the ac emitter resistance, re.
a. 15.762
b.
17.52
23 Ω
26 Q
Cc
Cce
CE
CWo
●●●
RL](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F29c8cf49-5423-4f4c-a559-4f2bc9841eaf%2F06b288e1-f5bb-48e8-a2d1-a00afbcf31d0%2Fvaxvga3_processed.png&w=3840&q=75)
Transcribed Image Text:Amplifier's Frequency Response
Vcc=20V
R1 = 40 kohm
R2 = 10 kohm
Rc = 4 kohm
RE=2 kohm
Rs = 1 kohm
RL = 2.2 kohm
Cs = 10 uF
Cc=1 uF
CE=20 uF
Cbc = 4 pF
Cbe = 36 pF
Cce 1 pF
Cwi=6 pF
Cwo = 8 pF
Beta = 100
+ I
Rs
V₂
2
Cs
+
R₁
Vcc
V₁ R₂ Cw₁
C.
d.
Cbc
Rc
Che
RE
Calculate the ac emitter resistance, re.
a. 15.762
b.
17.52
23 Ω
26 Q
Cc
Cce
CE
CWo
●●●
RL
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