Ampere's Law Four current carrying wires pierce though the path (with displacement vectors drawn) in the illustration. Suppose fë B. ds = 0. If current I₁ = 3.9A, what is current I (in Amps)? Figure [13.7] that
Ampere's Law Four current carrying wires pierce though the path (with displacement vectors drawn) in the illustration. Suppose fë B. ds = 0. If current I₁ = 3.9A, what is current I (in Amps)? Figure [13.7] that
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![Ampere's Law
Four current carrying wires
pierce though the path (with displacement
vectors drawn) in the illustration. Suppose
that
$
current I (in Amps)? Figure [13.7]
——
B. ds = 0. If current l₁
=
Type your response
dš
ds
I
ܐ
'I₁
d's
x 4A
x 2A
dš
3.9A, what is](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F99e37c92-095a-4cae-adf6-01aeaaa5668c%2F15c149d7-8e7f-48f7-9a87-af1f1266d84f%2Ft1vtgt5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Ampere's Law
Four current carrying wires
pierce though the path (with displacement
vectors drawn) in the illustration. Suppose
that
$
current I (in Amps)? Figure [13.7]
——
B. ds = 0. If current l₁
=
Type your response
dš
ds
I
ܐ
'I₁
d's
x 4A
x 2A
dš
3.9A, what is
![Path Integral The imaginary triangle loop in
figure 13.4 is now subjected to a downward
magnetic field of strength B=7T as in the
illustration. What is the value of the path
integral, f Bds (in Tm), given the
integration direction?
Type your response
y(m)
(3,4)
90°-0 d5₂
ds3
d5 (30)
B
x (m)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F99e37c92-095a-4cae-adf6-01aeaaa5668c%2F15c149d7-8e7f-48f7-9a87-af1f1266d84f%2Fh8hir1e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Path Integral The imaginary triangle loop in
figure 13.4 is now subjected to a downward
magnetic field of strength B=7T as in the
illustration. What is the value of the path
integral, f Bds (in Tm), given the
integration direction?
Type your response
y(m)
(3,4)
90°-0 d5₂
ds3
d5 (30)
B
x (m)
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