Ammoniacal nitrogen can be determined by treatment of the sample with chloroplatinic acid; the product is slightly soluble ammonium chloroplatinate: H₂PtCl 6 + 2 NH4+* --> (NH4)2PtCl6 + 2H+ The precipitate decomposes on ignition, yeilding metallic platinum and gaseous products: (NH4)2PtCl6 --> Pt (s) + 2 Cl2 (g) + 2 NH3 (g) + 2 HCI (g) Calculate the percentage of ammonium in a sample if 0.2235-g gave rise to 0.8218 - g of platinum (At Mass = 195.08 g/mol). The molecular weight of ammonia is 17.0306 g/mol.

Ammoniacal nitrogen can be determined by treatment of the sample with chloroplatinic acid; the product is slightly soluble ammonium chloroplatinate: H₂PtCl 6 + 2 NH4+* --> (NH4)2PtCl6 + 2H+ The precipitate decomposes on ignition, yeilding metallic platinum and gaseous products: (NH4)2PtCl6 --> Pt (s) + 2 Cl2 (g) + 2 NH3 (g) + 2 HCI (g) Calculate the percentage of ammonium in a sample if 0.2235-g gave rise to 0.8218 - g of platinum (At Mass = 195.08 g/mol). The molecular weight of ammonia is 17.0306 g/mol.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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