O STOICHIOMETRYSolving moles-to-moles lirniting reactant problemsAmmonia (NH,) gas and oxygen (02) gas react to form nitrogen (N2) gas and water (H,0) vapor. Suppose youhave 5.0 mol of NH, and 11.0 mol of O, in a reactor.Suppose as much as possible of the NH, reacts. How much will be left? Round your answer to the nearest 0.13.mol.dlbO molロExplanationCheck2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy AccessibilActivity DetailsV You have viewed this topicLast Visited Jan 31, 2021 4:00 PM

Answered: Ammonia (NH,) gas and oxygen (02) gas…

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter3: Molecules, Moles, And Chemical Equations

Section: Chapter Questions

Problem 3.81PAE: 3.81 The particulate scale drawing shown depicts the products of a reaction between H2 and O2...

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O STOICHIOMETRY
Solving moles-to-moles lirniting reactant problems
Ammonia (NH,) gas and oxygen (02) gas react to form nitrogen (N2) gas and water (H,0) vapor. Suppose you
have 5.0 mol of NH, and 11.0 mol of O, in a reactor.
Suppose as much as possible of the NH, reacts. How much will be left? Round your answer to the nearest 0.1
3.
mol.
dlb
O mol
ロ
Explanation
Check
2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy Accessibil
Activity Details
V You have viewed this topic
Last Visited Jan 31, 2021 4:00 PM

Expert Solution

Step 1

Ammonia reacts with oxygen to form nitrogen and water. The equation for the balanced chemical reaction is given below:

$4 {NH}_{3} + 3 O_{2} \to 2 N_{2} + 6 H_{2} O$

The stoichiometry of the balanced chemical reaction states that four moles of ammonia react with three moles of oxygen to form two moles of nitrogen and six moles of water.

The mole of ammonia (NH₃) is = 5.0 mol

The mole of oxygen (O₂) is = 11.0 mol

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