Ammonia (NH,) gas and oxygen (02) gas react to form nitrogen (N2) gas and water (H,0) vapor. Suppose you have 5.0 mol of NH, and 11.0 mol of O, in a reactor. Suppose as much as possible of the NH, reacts. How much will be left? Round your answer to the nearest 0.1 mol. I mol
Ammonia (NH,) gas and oxygen (02) gas react to form nitrogen (N2) gas and water (H,0) vapor. Suppose you have 5.0 mol of NH, and 11.0 mol of O, in a reactor. Suppose as much as possible of the NH, reacts. How much will be left? Round your answer to the nearest 0.1 mol. I mol
Chapter9: Chemical Quantities
Section: Chapter Questions
Problem 55A
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Transcribed Image Text:O STOICHIOMETRY
Solving moles-to-moles lirniting reactant problems
Ammonia (NH,) gas and oxygen (02) gas react to form nitrogen (N2) gas and water (H,0) vapor. Suppose you
have 5.0 mol of NH, and 11.0 mol of O, in a reactor.
Suppose as much as possible of the NH, reacts. How much will be left? Round your answer to the nearest 0.1
3.
mol.
dlb
O mol
ロ
Explanation
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Step 1
Ammonia reacts with oxygen to form nitrogen and water. The equation for the balanced chemical reaction is given below:
The stoichiometry of the balanced chemical reaction states that four moles of ammonia react with three moles of oxygen to form two moles of nitrogen and six moles of water.
The mole of ammonia (NH3) is = 5.0 mol
The mole of oxygen (O2) is = 11.0 mol
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