Ammonia gas can be prepared by the following reaction: CaO(s) + 2 NH4C1(s) →2 NH3(g) + H2O(g) + CaCl2 (s) If 480. g of CaO and 960. g of NH4CI are mixed, the theoretical yield of NH3 is 291 g. If only 147 g of NH3 is actually obtained, what is its percent yield?
Ammonia gas can be prepared by the following reaction: CaO(s) + 2 NH4C1(s) →2 NH3(g) + H2O(g) + CaCl2 (s) If 480. g of CaO and 960. g of NH4CI are mixed, the theoretical yield of NH3 is 291 g. If only 147 g of NH3 is actually obtained, what is its percent yield?
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![Ammonia gas can be prepared by the following reaction:
CaO(s) + 2 NH4 Cl(s)2 NH3 (g) + H2O(g) + CaCl, (s)
If 480. g of CaO and 960. g of NH4C1 are mixed, the theoretical yield of NH3 is 291 g. If only 147 g of NH3 is actually obtained, what is its percent
yield?
%
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Transcribed Image Text:Ammonia gas can be prepared by the following reaction:
CaO(s) + 2 NH4 Cl(s)2 NH3 (g) + H2O(g) + CaCl, (s)
If 480. g of CaO and 960. g of NH4C1 are mixed, the theoretical yield of NH3 is 291 g. If only 147 g of NH3 is actually obtained, what is its percent
yield?
%
Submit Answer
Try Another Version
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