Question.01A pulley of 150 mm effective diameter running at 1500 rev/min drives a follower of 750 mmdiameter, the two shafts being parallel, 1 m apart, and the free parts of the belt consideredstraight. The belt has a mass of 0.5 kg/m and the maximum tension is to be 800 N.If u= 0.35, estimate the maximum tension difference allowing for inertia of the belts.If the belt has a cross-sectional area of 350 mm? and E for the material is 320 MN/m?, estimatea) the speed of the driven pulley at the maximum condition, andb) the power transmitted to it.375 mm75mm1m Chapter 03: Belt DrivesSolutionReferring to Figure Q1Example C03.010-375 – 0-075cos- 0-3Question= 72° 33' = 1-266 radA pulley of 150 mm effective diameter running at 1500 rev/min drives a follower of 750 mmdiameter, the two shafts being parallel, 1 m apart, and the free parts of the belt consideredstraight. The belt has a mass of 0.4 kg/m and the maximum tension is to be 720 N... angle of lap on smaller pulley,0 = 2-532 radIf u= 0.4, estimate the maximum tension difference allowing for inertia of the belts.x 0-075 = 11-78 m/s60V= 1500 xIf the belt has a cross-sectional area of 320 mm? and E for the material is 300 MN/m?, estimatethe speed of the driven pulley at the maximum condition and the power transmitted to it.: Te= my?from equation (9(3.1)= 0-4 x 11-782 = 55-6 N一。公-”from equation (9 (3.2)720 - 55-6i.e.= *x26S2 = 2-754375 mmT, – 55-6-75mmT= 296-8 N:. T-T= 720– 296-8 = 423-2 Nfrom which=1-(T, - T,)from equation (9 **(3.10)1m423-2320 x 10- x 300 × 10°e 11:728 m/sFigure Q111-72860= 298-6 rov/min27. speed of follower=0-375Power transmitted = 423-2 x298-6 ×10-375 ) = 4960 W

ameter, the two shafts being parallel, 1 m apart, and the free parts of the belt considered raight. The belt has a mass of 0.5 kg/m and the maximum tension is to be 800 N. µ= 0.35, estimate the maximum tension difference allowing for inertia of the belts. the belt has a cross-sectional area of 350 mm² and E for the material is 320 MN/m², estimate a) the speed of the driven pulley at the maximum condition, and b) the power transmitted to it. 375 mm -75 mm 1m

ameter, the two shafts being parallel, 1 m apart, and the free parts of the belt considered raight. The belt has a mass of 0.5 kg/m and the maximum tension is to be 800 N. µ= 0.35, estimate the maximum tension difference allowing for inertia of the belts. the belt has a cross-sectional area of 350 mm² and E for the material is 320 MN/m², estimate a) the speed of the driven pulley at the maximum condition, and b) the power transmitted to it. 375 mm -75 mm 1m

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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