Amelia is de in the shape DE

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Problem: Surface Area Calculation**

Amelia is decorating the outside of a box in the shape of a square pyramid. The figure below shows a net for the box.

[Diagram Description: The diagram features a net for a square pyramid, which consists of a central square connected to four triangles, one on each side of the square. The side length of the square is 3.7 meters and the slant height of the triangle is 5 meters.]

**Question:**
What is the surface area of the box, in square meters, that Amelia decorates?

**Answer:**

\[ A = \quad \boxed{\quad} \, \text{m}^2 \]

**Explanations and Calculations:**

To find the surface area of the pyramid, we need to calculate the area of the base (square) and the area of the four triangular faces.

1. **Area of the Base (Square):**
    - Side length of the square is \( 3.7 \, \text{m} \).
    - Area of the square = \( \text{side}^2 = (3.7 \, \text{m})^2 = 13.69 \, \text{m}^2 \).

2. **Area of the Triangular Faces:**
    - There are 4 triangular faces.
    - Each triangle has a base equal to the side of the square (base = \( 3.7 \, \text{m} \)) and height (slant height) \( 5 \, \text{m} \).
    - Area of one triangle = \( \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 3.7 \, \text{m} \times 5 \, \text{m} = 9.25 \, \text{m}^2 \).
    - Total area of the four triangles = \( 4 \times 9.25 \, \text{m}^2 = 37 \, \text{m}^2 \).

3. **Total Surface Area:**
    - Surface area of the pyramid = Area of the base + Area of the four triangles = \( 13.69 \, \text{m}^2 + 37 \, \text{m}^2 = 50
Transcribed Image Text:**Problem: Surface Area Calculation** Amelia is decorating the outside of a box in the shape of a square pyramid. The figure below shows a net for the box. [Diagram Description: The diagram features a net for a square pyramid, which consists of a central square connected to four triangles, one on each side of the square. The side length of the square is 3.7 meters and the slant height of the triangle is 5 meters.] **Question:** What is the surface area of the box, in square meters, that Amelia decorates? **Answer:** \[ A = \quad \boxed{\quad} \, \text{m}^2 \] **Explanations and Calculations:** To find the surface area of the pyramid, we need to calculate the area of the base (square) and the area of the four triangular faces. 1. **Area of the Base (Square):** - Side length of the square is \( 3.7 \, \text{m} \). - Area of the square = \( \text{side}^2 = (3.7 \, \text{m})^2 = 13.69 \, \text{m}^2 \). 2. **Area of the Triangular Faces:** - There are 4 triangular faces. - Each triangle has a base equal to the side of the square (base = \( 3.7 \, \text{m} \)) and height (slant height) \( 5 \, \text{m} \). - Area of one triangle = \( \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 3.7 \, \text{m} \times 5 \, \text{m} = 9.25 \, \text{m}^2 \). - Total area of the four triangles = \( 4 \times 9.25 \, \text{m}^2 = 37 \, \text{m}^2 \). 3. **Total Surface Area:** - Surface area of the pyramid = Area of the base + Area of the four triangles = \( 13.69 \, \text{m}^2 + 37 \, \text{m}^2 = 50
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