Trevor Ariza is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 70% of the time. What is the probability of Trevor Ariza making none of his next 5 free throw attempts? Choose 1 answer:

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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**Transcription for Educational Website:**

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Trevor Ariza is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 70% of the time.

**What is the probability of Trevor Ariza making none of his next 5 free throw attempts?**

**Choose 1 answer:**

- **A)** \(0.70^5\)

- **B)** \(5 \times 0.70\)

- **C)** \(5 \times (1 - 0.70)\)

- **D)** \((1 - 0.70)^5\)

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### Explanation:

To find the probability that Trevor Ariza makes none of his next 5 free throw attempts, we need to consider the probability that he misses each one. Since he makes his free throws 70% of the time, the probability of missing a single free throw is \(30\%\) or \(0.30\).

Therefore, the probability of missing 5 consecutive free throws is calculated as:

- **Option D: \((1 - 0.70)^5\)**
Transcribed Image Text:**Transcription for Educational Website:** --- Trevor Ariza is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 70% of the time. **What is the probability of Trevor Ariza making none of his next 5 free throw attempts?** **Choose 1 answer:** - **A)** \(0.70^5\) - **B)** \(5 \times 0.70\) - **C)** \(5 \times (1 - 0.70)\) - **D)** \((1 - 0.70)^5\) --- ### Explanation: To find the probability that Trevor Ariza makes none of his next 5 free throw attempts, we need to consider the probability that he misses each one. Since he makes his free throws 70% of the time, the probability of missing a single free throw is \(30\%\) or \(0.30\). Therefore, the probability of missing 5 consecutive free throws is calculated as: - **Option D: \((1 - 0.70)^5\)**
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