OTribbles (fictional space creatures) have four, with three independentlyassorting loc. that all shows complete dominance controlling thephenotype as follows:• Locus P controlsfur curl, with W=way fur & straight furfour pigment, with P-pink fur + p=blue four• Locus I controls pigment deposition and withincts with loensP, with D = four color is expressed, and d= no pigment deposited,resulting in a black tribblecentralsSuppose that a crass- occursbetogeeni posents thatWPDphenotype individual withcoere frue -bocceding (10PD) x upD)• an• acompletely heterozygous individualWhat are the probabilties of the follow y phenstypes ?Black TribbleBlue tribble withwavyhair

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Description: OTribbles (fictional space creatures) have four, with three independentlyassorting loc. that all shows complete dominance controlling thephenotype as follows:• Locus P controlsfur curl, with W=way fur & straight furfour pigment, with P-pink fur + p=

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• am WTD phenotype individual with parents that Loere frue - breeding (LOPD) x up() completely heterozygous individual . a

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter12: Mendel, Genes, And Inheritance

Section: Chapter Questions

Problem 7TYK: In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene...

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In mice there are two loci responsible for coat color: Locus 1B- determines whether hair has bands: B- results in hair with bands & produces an agouti coat pigment (brown) b- homozygotes have no bands & their coat pigment is black Locus 2A- affects enzymes responsible for pigment production: A- results in normal pigment production a- homozygotes block all of the pigment production & are albino (white) What are the possible genotypes & phenotypes of the progeny if you were to cross 2 mice, which are heterozygous for both traits? What type of gene action is being expressed in this example?
The ABO blood groups in humans are expressed as the IA,IB and i alleles. The IAallele encodes the A blood group antigen, IB encodes B, and i encodes O. Both A and B are dominant to 0. If a heterozygous blood type A parent (IAi) and a heterozygous blood type B parent (IBi) mate, one quarter of their offspring are expected to have the AB blood type IAIBin which both arnigens are expressed equally. Therefore, ABO blood groups are an example of: a. multiple alleles and incomplete dominance b. codominance and incomplete dominance c. incomplete dominance only d. multiple alleles and codominance
In rabbits fur colour can be either gray black or blotchy. Blotchy is present as grey and black spots present in no specific pattern males are almost always are the grey or black while females can be gray, black or blotchy. However, a male individual is found that shows the blotchy pattern, and you, expect a nondisjunction event might to be to blame. Explain the inheritance of coat colour in rabbits and also provide an explanation for the blotchy male.
. Consider the genotypes of two lines of chickens: thepure-line mottled Honduran is i/i ; D/D ; M/M ; W/W, andthe pure-line leghorn is I/I ; d/d ; m/m ; w/w, whereI = white feathers, i = colored feathersD = duplex comb, d = simplex combM = bearded, m = beardlessW = white skin, w = yellow skinThese four genes assort independently. Starting withthese two pure lines, what is the fastest and mostconvenient way of generating a pure line that has coloredfeathers, has a simplex comb, is beardless, and has yellowskin? Make sure that you showa. the breeding pedigree.b. the genotype of each animal represented.c. how many eggs to hatch in each cross, and why thisnumber.d. why your scheme is the fastest and the mostconvenient
In rabbits, fur colour can be either grey, black or blotchy. Blotchy is present as grey and black spotspresent in no specific pattern. Males are almost always either grey or black, while females can begrey, black or blotchy. However, a male individual is found that shows the blotchy pattern, and youexpect a non-disjunction event might be to blame. Explain the inheritance of coat colour in rabbits,and also provide an explanation for the blotchy male.
Highlight Draw ソeu र In guinea pigs, short hair is dominant over long hair. If a short haired SS guinea pig is erossed with a long haired ss guinea pig, what are the possible genotypes and phenotypes of their offspring and the percent chance of each? 3. S Fill in the table: Genotype Phenotype Chance
5 f There are two genes that determine the coat colour expression in dogs: eumelanin and merle. These genes are located on two separate chromosomes. For the eumelanin gene, black coat colour (E) is dominant over red coat colour (e). The merle gene controls the degree to which these coat colours are expressed through incomplete dominance. The following table describes the merle gene expression. Genotype MM Mm mm Phenotype White AAY Half colour (Grey or light red) Full colour (Black or Red) 1. If a dog breeder wants to determine the unknown genotype of a dog, what colour of dog must she use as a testcross? 2. A white dog was testcrossed, and all of the puppies had light red coats. What is the genotype of the white dog? Use a Punnett square to show your work. Hint - When a trait is controlled by two genes, an individual's genotype consists of 4 letters. = = = B I 123 ||| 14 E E I ос C GO * ●● ● ●0 00 00 00 ✓ C U up X₂ x²
In humans, tongue rolling (R) is completely dominant to the inability to roll the tongue (r), unattached earlobes (E) are completely dominant to attached earlobes (e), • presence of dimples (D) is completely dominant to the absence of dimples (d), • and a peaked hairline (H) is completely dominant to a straight hairline (h). A woman of genotype rr Ee DD Hh and a man of genotype Rr Ee Dd hh are planning to have a child. What is the probability that: i. The child will show the recessive trait for all four characteristics? 11. The child will look like its mother for all four characteristics? The the child will not look like its father for all four characteristics? 111.
Let’s look at hair texture. Some people have curly hair, some have straight hair and some express a traitthat is in-between (Incomplete Dominance), or wavy hair. Therefore curly and straight are bothhomozygous and wavy is the expression of the heterozygous condition. Instead of using capital and lowercase letters, we’ll add a prime (`) to the letter. This is because one is not dominant over the other, andthey will both contribute to the phenotype. We can use H to indicate curly hair and H` to indicate straighthair.Given this information, complete the square: Parent Phenotype(appearance) Genotype(alleles) 1 Curly hair HH 2 Straight hair H'H' Do you remember where the alleles of each parent go?Parents: Offspring: Genotypes: Phenotypes: What are the potential phenotypes and genotypes of the offspring?
Incomplete Dominance/Codominance By Tara Chavez. Due on May 7th, 4:00pm Incomplete Dominance r Соpy link 三 MULTIPLE CHOICE QUESTION R RR Rr If you cross a red snapdragon with a white snapdragon what phenotype should you expect in 100% of the offspring if snapdragon flowers are expressed via incomplete dominance? Rr r Pink Red YouTube Rr White Lenovo !!!
O e. Parent 2: Parent 1: Parent 2: ¡Ai QUESTION 9 Bi QUESTION 8 Let's assume that, in dragons, red scales (B) are dominant to green scales (b), and long tongues (S) are dominant to short tongues (s). The genes that determine these characteristics assort independently. A homozygous red, long-tongued dragon is crossed with a homozygous green, short-tongued dragon. If an F1 dragon is crossed to a homozygous green and homozygous short-tongued dragon, what phenotypes and proportions are expected in the offspring? O a. 100% green and long-tongued O b. ½ green and short-tongued & ½ red and long-tongued O c. ½ red and short-tongued & ½ green and long-tongued O d.% red and long-tongued, % red and short-tongued, ½ green and long-tongued, % green and short-tongued O e. 9/16 red, long-tongued, 3/16 green, long-tongued, 3/16 red, short-tongued, 1/16 green, short-tongued Save and Submit to save and submit. Click Save All Answers to save all answers. 000 MacBook Air
F1 female Drosophila heterozygous for cinnabar eye (cn), vestigial wings (vg) and roof wings (rf) genes were test crossed with males homozygous for all three traits. The following result were obtained. 382 cinnabar, vestigial 401 roof 3 cinnabar 4 roof, vestigial 59 cinnabar, roof, vestigial 67 wild 44 cinnabar, roof 40 vestigial The chromosomal interference is equal to? 0.24 0.32 0.42 0.58 0.49