am needing assistance making the changes the instructor requested be changed on this question. Thank you.  Scenario:Is there a relationship between one’s gender and whether one owns a dog, cat, or reptile? Use the data provided in the table below to answer the following questions. Question: Using the degrees of freedom provided by your SPSS output and an alpha value of .05, find the critical value in the appropriate table in the Appendix of your Jackson e-book. Do not round – present all three decimal places. Clearly identify the critical value from your e-book and the obtained value from your SPSS output. Based on this information, would you reject or fail to reject the null hypothesis? Does this mean there is a significant difference or no significant difference?    My Answer:  The chi-square test of significance between the gender and pets owned is shown. The findings indicate that, with a p-value of 0.177, which is higher than the alpha value, there was no statistically significant relationship between gender and the number of owned pets at 2 degrees of freedom. Since the alternative hypothesis is rejected, we accept the null hypothesis.Alternative Hypothesis: There is a significant relationship between the pets owned and gender.Null Hypothesis: No significant relationship exists between the pets owned and gender. Instructor Feedback: what is the critical value? we don't reject the alternative - we test the null

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I am needing assistance making the changes the instructor requested be changed on this question. Thank you. 

Scenario:Is there a relationship between one’s gender and whether one owns a dog, cat, or reptile? Use the data provided in the table below to answer the following questions.

Question: Using the degrees of freedom provided by your SPSS output and an alpha value of .05, find the critical value in the appropriate table in the Appendix of your Jackson e-book. Do not round – present all three decimal places. Clearly identify the critical value from your e-book and the obtained value from your SPSS output. Based on this information, would you reject or fail to reject the null hypothesis? Does this mean there is a significant difference or no significant difference?  

 My Answer: 

The chi-square test of significance between the gender and pets owned is shown. The findings indicate that, with a p-value of 0.177, which is higher than the alpha value, there was no statistically significant relationship between gender and the number of owned pets at 2 degrees of freedom. Since the alternative hypothesis is rejected, we accept the null hypothesis.Alternative Hypothesis: There is a significant relationship between the pets owned and gender.Null Hypothesis: No significant relationship exists between the pets owned and gender.

Instructor Feedback: what is the critical value? we don't reject the alternative - we test the null

 

6. Paste all relevant statistical output in the space provid
ANSWER
Gender Scores
Gender
Total
Male
Female
Pearson Chi-Square
Likelihood Ratio
N
Case Processing Summary
Cases
Missing
Valid
101
Percent
100.0%
Count
Expected Count
Count
Expected Count
Count
Expected Count
Gender Scores Crosstabulation
Chi-Square Tests
Value
3,467
3.518
1.724
Dog
N
20
214
25
23.6
45
45.0
5
of
0
222
Percent
Scores
Cat
0.0%
70309
17
Linear-by-Linear Association
N of Valid Cases
101
a 0 cells (0.0%) have expected count less than 5. The minimum
expected count is 7.60.
19.0
23
21.0
401
40.0
Asymptotic
Significance (2-
sided)
Reptiles
N
177
172
189
11
7.6
5
8.4
16
16.0
Total
Percent
101 100.0%
Total
48
48.0
53
53.0
101
101.0
73
Transcribed Image Text:6. Paste all relevant statistical output in the space provid ANSWER Gender Scores Gender Total Male Female Pearson Chi-Square Likelihood Ratio N Case Processing Summary Cases Missing Valid 101 Percent 100.0% Count Expected Count Count Expected Count Count Expected Count Gender Scores Crosstabulation Chi-Square Tests Value 3,467 3.518 1.724 Dog N 20 214 25 23.6 45 45.0 5 of 0 222 Percent Scores Cat 0.0% 70309 17 Linear-by-Linear Association N of Valid Cases 101 a 0 cells (0.0%) have expected count less than 5. The minimum expected count is 7.60. 19.0 23 21.0 401 40.0 Asymptotic Significance (2- sided) Reptiles N 177 172 189 11 7.6 5 8.4 16 16.0 Total Percent 101 100.0% Total 48 48.0 53 53.0 101 101.0 73
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I am still struggling to identify the exact critical value of this write-up. Can you please clarify only the critical value? THank you. 

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