am needing an algorithm (some linear sort) that runs in O(n^2) time that will compar the number in two sets of data (arrays) and return the numbers that equal each other What algorithm would run this in O(n lg n) time?

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Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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I am needing an algorithm (some linear sort) that runs in O(n^2) time that will compar the number in two sets of data (arrays) and return the numbers that equal each other

What algorithm would run this in O(n lg n) time?

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Step 1

What algorithm would run this in O(n.logn) time?

Answer:

we can use binary search for O(n.logn) and we can do this using O(n) as well 

the following also will take the O(n) :

int printCommon(int arr1[], int len1, int arr2[], int len2) {
 
   int i=0,j=0;
 
   while(len1 > i && len2 > j){
 
      if (arr1[i] < arr2[j]) { 
          i++;
 
       }else if(arr2[j] < arr1[i]){
         j++;
 
       } else {
 
        printf("\nCommon element is %d",arr1[i]);
        i++;
        j++;
      }
   }
 
}
 

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