Aluminum reacts with chlorine to form aluminum chloride. The equation for this reaction is 2 AlI(s) + 3 Cl2(g) → 2 AICI3(s). What is the percentage yield for a reaction in which 33.5 g of aluminum is reacted with excess chlorine to produce 164.5 g of aluminum chloride? Use the molar mass values given here. MAI = 26.9815 g/mol %3D MCl2 = 70.9064 g/mol MAIC13 = 133.3411 g/mol %3D

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Aluminum reacts with chlorine to form aluminum chloride. The equation for this
reaction is 2 AlI(s) + 3 Cl2(g) → 2 AICI3(s). What is the percentage yield for a reaction
in which 33.5 g of aluminum is reacted with excess chlorine to produce 164.5 g of
aluminum chloride? Use the molar mass values given here.
MAI = 26.9815 g/mol
%3D
MCl2 = 70.9064 g/mol
%3D
MAICI3 = 133.3411 g/mol
%3D
66.8 %
100.6
99.4 %
49.7 %
Transcribed Image Text:Aluminum reacts with chlorine to form aluminum chloride. The equation for this reaction is 2 AlI(s) + 3 Cl2(g) → 2 AICI3(s). What is the percentage yield for a reaction in which 33.5 g of aluminum is reacted with excess chlorine to produce 164.5 g of aluminum chloride? Use the molar mass values given here. MAI = 26.9815 g/mol %3D MCl2 = 70.9064 g/mol %3D MAICI3 = 133.3411 g/mol %3D 66.8 % 100.6 99.4 % 49.7 %
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