alternatingSum: Given a list of integers, compule the alternating sum of its elements. 3 (bc 1 10 (b/c e # [1, 2, 3, 4, 5] -> # [@ , 1© , 20] -> : [9, 9, 9, 9] -> o (b/c 9 - 9 + 9 - 9 = 0) def alternatingSum(nums): 2 + 3 - 4 + 5 = 3) 10 + 20 = O) %3D
alternatingSum: Given a list of integers, compule the alternating sum of its elements. 3 (bc 1 10 (b/c e # [1, 2, 3, 4, 5] -> # [@ , 1© , 20] -> : [9, 9, 9, 9] -> o (b/c 9 - 9 + 9 - 9 = 0) def alternatingSum(nums): 2 + 3 - 4 + 5 = 3) 10 + 20 = O) %3D
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Python
![elements.
# [1, 2, 3, 4, 5]
# [o , 10 , 2o] ->
-> з (bc 1
10 (b/c o
# [9, 9, 9, 9] -> o (b/c 9 -9 + 9 -9 = 0)
4 + 5 = 3)
= 0 )
- 2 + 3
10 + 20
%3D
def alternatingSum(nums):](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fca5180bd-cde8-42eb-9776-5c2dffaa1f36%2F1fb0cfd5-5743-46ab-865f-9d7831e26d06%2Fpi50vvh_processed.png&w=3840&q=75)
Transcribed Image Text:elements.
# [1, 2, 3, 4, 5]
# [o , 10 , 2o] ->
-> з (bc 1
10 (b/c o
# [9, 9, 9, 9] -> o (b/c 9 -9 + 9 -9 = 0)
4 + 5 = 3)
= 0 )
- 2 + 3
10 + 20
%3D
def alternatingSum(nums):
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