Also, the forces must be in vector form. For this part of the lab, you must develop a script that does the following: 1. Require the user to input a position vector, then the corresponding force, until there are no more forces in the system. You can have the user type in 0 to stop the script from asking for more. 2. Utilize the cross command to calculate the cross product 3. Use the fprintf command to out the Moment in cartesian, vector form. Meaning you have to have the unit base vectors i, j, & k and the proper units. 4. The program can take in any position vectors and corresponding forces. 5. Hint: The 150 N force is directed in the negative direction and its vector is: F₁ = -150k N. The position of this force is r₁ = 21 m 6. Hint: The 200 N force is directed in the positive y direction and its vector is: F₂ = 200j N. The position of this force is r₂ = 2.5i-2j m
Also, the forces must be in vector form. For this part of the lab, you must develop a script that does the following: 1. Require the user to input a position vector, then the corresponding force, until there are no more forces in the system. You can have the user type in 0 to stop the script from asking for more. 2. Utilize the cross command to calculate the cross product 3. Use the fprintf command to out the Moment in cartesian, vector form. Meaning you have to have the unit base vectors i, j, & k and the proper units. 4. The program can take in any position vectors and corresponding forces. 5. Hint: The 150 N force is directed in the negative direction and its vector is: F₁ = -150k N. The position of this force is r₁ = 21 m 6. Hint: The 200 N force is directed in the positive y direction and its vector is: F₂ = 200j N. The position of this force is r₂ = 2.5i-2j m
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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