Alpha particles of kinetic energy K are scattered either from a gold foil or a silver foil of identical thickness. What is the ratio of the number of particles scattered at angles greater than 90° by the gold foil to the same number for the silver foil?
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Q: The isotope of Nickel, 66Ni decays by β emission, has a half-life of 2.3 days. and the β particles…
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Q: The isotope of Nickel, 66Ni decays by β emission, has a half-life of 2.3 days. and the β particles…
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- The isotope of Nickel, 66Ni decays by β emission, has a half-life of 2.3 days. and the β particles have an average energy of 65 keV. A source consisting of this isotope has an initial number of atoms N0 = 5 x 1020 atoms. What is the power per unit area initially deposited by this source in a small target placed at 1m distance from the source? Select one: a. 35 W/m2 b. 1.45 W/m2 c. 4.5 kW/m2 d. 7.6 MW/m23. a) Alpha particles of the same initial speed are shot at the same intensity toward gold, silver, and aluminum foils of the same thickness. They are observed at a detector at a fixed scattering angle, 0 0°. What would the ratios of the number of alpha particles scattered by the gold and silver foils to the aluminum foil, No Au 13). NaAl and respectively, be? (ZAu = 79, ZAg = 47, ZAI Na Ag NaAl b) Compare the number of a particles of fixed kinetic energy scattered through an angle of 10° (call this Na(10°)) with the number scattered through an angle of 20° (Na (20°)) for Rutherford scattering by a thin gold foil of fixed thickness. Compute Na (10⁰) Na (20°). p2 Rutherford's scattering model assumes that the alpha particles experience a Coulomb repulsion, F = KqZe from the nucleus of the foil's atom. If, in a head-on collision the alpha particle has enough energy to get inside a uniformly charged Kqa Zer nucleus of radius R, the force law would change to F = R³ " point-nucleus…Consider the nuclear fusion reaction 3H+ 'He > 'H + 'He. Part A Compute the binding energy of the H. Express your answer in mega-electron volts to three significant figures. B = MeV Submit Previous Answers Request Answer Part B Compute the binding energy of the He. Express your answer in mega-electron volts to three significant figures. ? B = MeV Submit Previous Answers Request Answer Part C Compute the binding energy of the H. Express your answer in mega-electron volts to three significant figures. ? B = MeV Submit Request Answer Part D Compute the binding energy of the "He. Express your answer in mega-electron volts to three significant figures. B = MeV
- question 4 pleaseIn a high-energy electron scattering experiment on the nucleus, a scientist has scientist has possibilities to use energies of 200, 2000 and 20000 MeV. Which energy should the scientist use? Do the calculations and give the necessary arguments to show why the scientist makes the right decision.Part A Calculate (in MeV) the total binding energy for 40 Ar. Express your answer in mega-electron volts to four significant figures. ? MeV Submit Previous Answers Request Answer X Incorrect; Try Again; 7 attempts remaining Part B Calculate (in MeV) the binding energy per nucleon for 40 Ar. Express your answer in mega-electron volts to three significant figures. Ην ΑΣφ ? Var = MeV Submit Request Answer Part C Calculate (in MeV) the total binding energy for 40K. Express your answer in mega-electron volts to four significant figures. nνα ΑΣφ ? BK = MeV Submit Previous Answers Request Answer
- Alpha particles of kinetic energy 6.9M V are incident at a rate of 3.1x 10" per second on a copper foil of thickness 3.1 x 10-m. A circular detector of diameter 1.0cm is placed 13cm from the foil at an angle of 30° with the direction of the incident alpha particles. At what rate does the detector measure scattered alpha particles? (The molar mass of copper is 63.5 and its density is 8.9em-)A, Explain the importance of reducing exposure dose and time to a patient undergoing a diagnostic X-ray examination. Describe ways to achieve this. B, Calculate the wavelength of the most energetic X-rays produced by tube operating at pd of 1×10^6 V, h= 6.6×10^(-34) J, e=1.6×10^(-19) C, c=3×10^8 ms^(-1)The number of atoms in 1mg of radium is 2.66 * 1018 how to calculate the activity of a 1mg sample of radium ?