Almost áll êmployees working for financial companies in New York City receive large bonuses at the end of the year. A sample of 63 employees selected from financial companies in New York City showed that they received an average bonus of $46,000 last year with a standard deviation of $21,000. Construct a 95% confidence interval for the average bonus that all employees working for financial companies in New York City received last year. Round your answers to cents. %$i to $ i


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Obtain the 95% confidence interval for the average bonus that all employees working for financial companies in New York city received last year.
The 95% confidence interval for the average bonus that all employees working for financial companies in New York city received last year is obtained below:
The formula for the Confidence interval for mean is:
Obtain the degrees of freedom.
From the information, given that there is a sample of 63.
The degrees of freedom is obtained below:
Use EXCEL Procedure for finding the critical value of t.
Follow the instruction to obtain the critical value of t:
- Open EXCEL
- Go to Formula bar.
- In formula bar enter the function as“=TINV”
- Enter the probability as 0.05.
- Enter the degrees of freedom as 62.
- Click Enter.
EXCEL output:
From the EXCEL output, the critical value of t at the 0.05 level of significance with the 62 degrees of freedom is 1.998971
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