Allied Corporation is trying to determine whether to purchase Machine A or B. It has leased the two machines for amonth. A random sample of 5 employees has been taken. These employees have gone through a training session onboth machines. Below you are given information on their productivity rate on both machinesProductivity RatePerson345Machine A4951545147Machine B25485476053Using a 01, test the hypothesis that productivity rate on Machine A and Machine B are different using bothp-value and rejection point approach.

It is required to test whether the productivity rates on Machines A and B are different at α = 0.01,…

Answered: Allied Corporation is trying to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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We want to investigate the average study time per day of School students. The official number of School students is 20,000. We have collected data using the actual contact number of School students. It contains individual-level information on the study hours per day. The number of observations in a data set is 20,000. The same person has not been collected more than once in this data. According to this data, the average study time per day of School students is 3 hours and 20 minutes. 1.what's unique about this data 2.how do you perform your own hypothesis test using this data?
A researcher believes that there may be a negative association between the quantity of fertilizer used and the percentage of the population who live in rural areas in different countries. The data below shows the percentage of the population who live in rural areas and the fertilizer use measured in kg per hectare, for a random sample of 11 countries. 33%= 76kg, 6%=44kg, 58%= 6kg, 35%=68kg, 81%=3kg, 69%=10kg, 61%=7kg, 7%=176kg,74%=5kg, 71%=137kg, 17%=157kg Use the Spearman's rank order coefficient method to affirm or disagree with the researchers assumption.
The boxplot below shows salaries for CPAS and Actuaries in a town. СРА Actuary 20 30 40 50 60 70 80 90 100 110 Salary (thousands of $) If a person is making the third quartile salary for a CPA, they are making less than % of Actuaries.
Twenty samples of students from the first year were taken for the study related to fitness level in a university. The researcher has collected the data for a few variables: gender and fitness test score. Fitness Camp No Gender Fitness score Fitness score (Before Attend camp) (After Attend camp) 1 M 444 526 2 F 780 862 3 F 475 557 4 F 490 572 5 M 755 837 6. M 766 848 7 F 540 622 8 M 623 705 9. F 600 682 10 620 702 11 505 590 12 M 640 725 13 F 523 608 14 F 700 785 15 M 710 795 16 M 726 811 17 M 740 825 18 F 550 635 19 F 685 770 20 F 460 545 Range of Fitness Score: 0 to 900 1. Determine whether this set of data is sample or population? Why? Which formulae to be used when calculating the standard deviation of fitness score before and after camp 2. Calculate the standard deviation for fitness score before and after students attended the fitness camp for the whole samples using the formula in (1) 3. Based on the sample standard deviation in part (2), explain whether the fitness camp can…
A businesswoman is considering whether to open a coffee shop in a local shopping center. Before making this decision, she wants to know how much money people spend per week at coffee shops in that area. She took a random sample of 26 customers from the area who visit coffee shops and asked them to record the amount of money (in dollars) they would spend during the next week at coffee shops. At the end of the week, she obtained the following data (in dollars) from these 26 customers: 16.63 38.63 15.14 14.47 5.01 63.64 10.19 13.28 32.25 36.00 16.19 65.91 10.28 37.14 3.22 6.92 34.65 6.40 36.35 27.59 38.67 13.18 9.80 9.48 1.21 5.19 Assume that the distribution of weekly expenditures at coffee shops by all customers who visit coffee shops in this area is approximately normal. Round your answers to cents.a. What is the point estimate of the corresponding population mean?x¯=$b. Make a 99% confidence interval for the average amount of money spent per week at coffee shops by all…
Part 1 of 4 A doctor in Oklahoma City wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 10% level of significance to test whether the average life span of heart disease patients in Oklahoma City differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 8.1, 1.2, 7, 11.5, 21, 2, 15.3, 19.2, 10.5, 15.4, 12.7, 15.3, 12.1, 7.5, 11.4, 16.4, 26.7, 14.6, 1.5, 16.3, 12.6, 0.8, 18.2, 4.2, 9.6, 21, 16.3, 2.7 Life Span of Patients Treated at Hospital 2: 17.6, 11.6, 16.8, 5.2, 6.7, 3.2, 13.8, 12.5, 0.9, 6, 14.3, 1.8, 14.8, 10, 5.8, 15.2, 10, 3.7, 11.4, 21.6, 12.9, 0.5, 9.2, 13.9, 10.9 Life Span of Patients Treated at Hospital 3: 8.5, 2.3, 11, 7.4, 14.8, 5.8, 11, 3.4, 10.9, 1.1, 5.9, 21.6, 12.5, 0.1, 15.5, 15.4, 0.8, 7.7, 5.6, 12, 7.1 Life Span of Patients Treated at Hospital 4:…
On average, a sample of n = 36 scores will provide a better estimate of the population mean than a sample of n = 49 scores from the same population.
Suppose a biologist is studying the population of fish in freshwater lakes. He collects data on the number of different species of fish found in 20 lakes. The boxplot displays the results of the study with species of fish in intervals of 50. 100 150 200 250 300 350 400 450 500 550 600 Number of species of fish What is the value of the upper quartile for the data set. Round values to the nearest 25 species.
A father is concerned that his teenage son is watching too much television each day, since his son watches an average of 2 hours per day His son says that his TV habits are no different than those of his friends. Since this father has taken a stats class, he knows that can actually test to see whether or not his son is watching more TV than his peers The father collects a random sample of watching times from boys at his son's high school and gets the following data: 1.9, 2.3, 2.2, 1.9, 1.6, 2.6, 1.4, 2.0, 2.0, 2.2 Find a 95% confidence interval for the true mean number of hours teenagers at that school watch TV. a. Confidence Interval b. Conclusion
Clothes dried outside smell better than those dried in a dryer because of a process called photolysis. Sunlight breaks down compounds that cause odor. A trained smeller is asked to smell a random sample of 20 towels. The smeller does not know it, but all of the 20 towels have been dried in the sun. The smeller is blindfolded and is not allowed to touch the towels but leans forward to smell the towel then rates the towel on a smell-scale of 1 to 10, where 1 is the an extremely unpleasant smell and 10 is a very good smell. A smell rating of 8 is typically attributed to a towel that is dried in the dryer. The mean smell rating for these 20 towels is approximately normal with a mean of 8.45 and the standard deviation is 0.887. A statistician performs a test of Ho μ = 8 versus H₁ μ> 8 where is the true mean smell rating for all towels dried in the sun. This test yields a P-value of 0.0176. What conclusion would you make at the significance level a = 0.05? Because the P-value of 0.0176 < α =…

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