ALL BUT ONE of the following sentences provide reasonable explanations for the overall trend and the irregularities observed in the second ionization energies (i.e., IE2) of the elements whose cations are shown in the table. Identify the one statement that is INCORRECT, Na Mg Al Si Pt St CI Art IE (kJ/mol] 4562 1451 1817 1577 1903 2251 2297 2665 Select one: O a. Electrons in the same orbital repel each other slightly, even though the electrons are allowed to pair in the same orbital. Eliminating this pairing energy is the reason why the IE of Al' is higher than the IE of Al O b. While the atomic number increases across a row of the periodic table, the effective nuclear charge increases. This increased attraction to the nucleus causes the general trend in jonization energy. O c. Removing an extra electron from the full valence shell of Na' involves losing an electron from the n=2 level, which feels much less shielding than an n=3 electron. That is why the IE, of Na is so much larger than the IE, of Mg. O d. Electrons in the same orbital repel each other slightly, so removing a paired electron from ap orbital is slightly easier than expected. That is why the IE of Si is surprisingly lower than the IE of Al'. Notes (+

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ALL BUT ONE of the following sentences provide reasonable explanations for the overall trend and the irregularities observed in the second ionization
energies (i.e., IE2) of the elements whose cations are shown in the table. Identify the one statement that is INCORRECT.
Na*
Mg
Al
Si
St
CI
Ar
IE (kJ/mol]
4562
1451
1817
1577
1903 2251 2297 2665
Select one:
O a. Electrons in the same orbital repel each other slightly, even though the electrons are allowed to pair in the same orbital. Eliminating this pairing energy is the reason why the IE of Al
is higher than the IE of Al
O b. While the atomic number increases across a row of the periodic table, the effective nuclear charge increases. This increased attraction to the nucleus causes the general trend in
ionization energy.
O c. Removing an extra electron from the full valence shell of Na' involves losing an electron from the n=2 level, which feels much less shielding than an n=3 electron. That is why the
IE2 of Na is so much larger than the IE2 of Mg.
O d. Electrons in the same orbital repel each other slightly, so removing a paired electron from a p orbital is slightly easier than expected. That is why the IE of Si' is surprisingly lower
than the IE of Al
Notes (+
Transcribed Image Text:ALL BUT ONE of the following sentences provide reasonable explanations for the overall trend and the irregularities observed in the second ionization energies (i.e., IE2) of the elements whose cations are shown in the table. Identify the one statement that is INCORRECT. Na* Mg Al Si St CI Ar IE (kJ/mol] 4562 1451 1817 1577 1903 2251 2297 2665 Select one: O a. Electrons in the same orbital repel each other slightly, even though the electrons are allowed to pair in the same orbital. Eliminating this pairing energy is the reason why the IE of Al is higher than the IE of Al O b. While the atomic number increases across a row of the periodic table, the effective nuclear charge increases. This increased attraction to the nucleus causes the general trend in ionization energy. O c. Removing an extra electron from the full valence shell of Na' involves losing an electron from the n=2 level, which feels much less shielding than an n=3 electron. That is why the IE2 of Na is so much larger than the IE2 of Mg. O d. Electrons in the same orbital repel each other slightly, so removing a paired electron from a p orbital is slightly easier than expected. That is why the IE of Si' is surprisingly lower than the IE of Al Notes (+
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