ALKENE Br₂ Br H... H3C Br ""H CH3

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What is the alkene reactant 

**Alkene Halogenation Reaction**

The image illustrates the halogenation reaction of an alkene using bromine (Br₂) as a halogen source. 

1. **Reactant**: The left side of the image represents an alkene, indicated by the label "ALKENE." An alkene is a hydrocarbon that contains at least one carbon–carbon double bond (C=C).

2. **Reaction Arrow**: The arrow pointing from the alkene to the product signifies the chemical reaction taking place. Above the arrow, Br₂ is written, representing bromine molecules as the reactant.

3. **Product**: On the right side of the image, the product of the halogenation reaction is shown. The product is a dibromoalkane, specifically with two bromine (Br) atoms added across the former double bond of the alkene. In this case, the resulting compound is a dibrominated alkane where the bromine atoms are bonded to two carbon atoms that were previously double-bonded.

4. **Stereochemistry**: The product shows the addition of Br₂ to the alkene in an anti addition manner. This means the two bromine atoms are added on opposite sides of the former double bond, resulting in a trans configuration relative to each other, ensuring that the molecule formed is more stable.

**Detailed Structural Explanation**:
- **Br**: Bromine atoms are shown attached to the carbon atoms which were previously part of the double bond.
- **H₃C and CH₃**: Methyl (CH₃) groups are attached to the remaining carbon atoms.
- **H**: Hydrogen atoms are also bonded to the carbon atoms adjacent to the one bonded with bromine.
- The dashed and solid wedges indicate the three-dimensional spatial arrangement of the bromine and hydrogen atoms around the carbon atoms.

This reaction is a key example of how alkenes undergo addition reactions, where the double bond is broken, and new atoms are added to the carbon atoms. This is a fundamental concept in organic chemistry, highlighting the reactivity of alkenes and the formation of more complex molecules through functional group transformations.
Transcribed Image Text:**Alkene Halogenation Reaction** The image illustrates the halogenation reaction of an alkene using bromine (Br₂) as a halogen source. 1. **Reactant**: The left side of the image represents an alkene, indicated by the label "ALKENE." An alkene is a hydrocarbon that contains at least one carbon–carbon double bond (C=C). 2. **Reaction Arrow**: The arrow pointing from the alkene to the product signifies the chemical reaction taking place. Above the arrow, Br₂ is written, representing bromine molecules as the reactant. 3. **Product**: On the right side of the image, the product of the halogenation reaction is shown. The product is a dibromoalkane, specifically with two bromine (Br) atoms added across the former double bond of the alkene. In this case, the resulting compound is a dibrominated alkane where the bromine atoms are bonded to two carbon atoms that were previously double-bonded. 4. **Stereochemistry**: The product shows the addition of Br₂ to the alkene in an anti addition manner. This means the two bromine atoms are added on opposite sides of the former double bond, resulting in a trans configuration relative to each other, ensuring that the molecule formed is more stable. **Detailed Structural Explanation**: - **Br**: Bromine atoms are shown attached to the carbon atoms which were previously part of the double bond. - **H₃C and CH₃**: Methyl (CH₃) groups are attached to the remaining carbon atoms. - **H**: Hydrogen atoms are also bonded to the carbon atoms adjacent to the one bonded with bromine. - The dashed and solid wedges indicate the three-dimensional spatial arrangement of the bromine and hydrogen atoms around the carbon atoms. This reaction is a key example of how alkenes undergo addition reactions, where the double bond is broken, and new atoms are added to the carbon atoms. This is a fundamental concept in organic chemistry, highlighting the reactivity of alkenes and the formation of more complex molecules through functional group transformations.
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