The image shows a chemical equation related to acid-base chemistry. The formula is expressed as: \[ C_T = [H^+] \left( 1 + \frac{[H^+]}{K_a} \right) \] Below the equation, two values are provided: - \( C_T = 9.5 \times 10^{-5} \) - \( K_a = 10^{-7.6} \) The unknown in the equation is: \[ [H^+] = ? \] This equation is used to find the concentration of hydrogen ions \([H^+]\) in a solution. It relates the total concentration of the acid \(C_T\), the hydrogen ion concentration \([H^+]\), and the acid dissociation constant \(K_a\).

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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What are the algebraic steps to isolate [H+] so I can solve for it with given variables?

The image shows a chemical equation related to acid-base chemistry. The formula is expressed as:

\[ C_T = [H^+] \left( 1 + \frac{[H^+]}{K_a} \right) \]

Below the equation, two values are provided:

- \( C_T = 9.5 \times 10^{-5} \)
- \( K_a = 10^{-7.6} \)

The unknown in the equation is:

\[ [H^+] = ? \]

This equation is used to find the concentration of hydrogen ions \([H^+]\) in a solution. It relates the total concentration of the acid \(C_T\), the hydrogen ion concentration \([H^+]\), and the acid dissociation constant \(K_a\).
Transcribed Image Text:The image shows a chemical equation related to acid-base chemistry. The formula is expressed as: \[ C_T = [H^+] \left( 1 + \frac{[H^+]}{K_a} \right) \] Below the equation, two values are provided: - \( C_T = 9.5 \times 10^{-5} \) - \( K_a = 10^{-7.6} \) The unknown in the equation is: \[ [H^+] = ? \] This equation is used to find the concentration of hydrogen ions \([H^+]\) in a solution. It relates the total concentration of the acid \(C_T\), the hydrogen ion concentration \([H^+]\), and the acid dissociation constant \(K_a\).
Expert Solution
Step 1

Given that, CT=9.5×10-5 and Ka=10-7.6

To find the value of H+, substitute the given values in  CT=H+1+H+Ka.

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