Alex has developed a new interplanetary grandfather clock for a Mars colony with an adjustable length pendulum. For it to keep perfect 24-hour time, The pendulum length is set so the period is 2.000 s here on Earth. (gEarth = 9.81 m/2) a) What is the pendulum's length on Earth? b) The clock will first be set up on the Luna, the Earth's moon. To keep the same 24- hour-a-day time in Luna's gravity (gLuna = 1.635 m/s?), what is the pendulum length? c) Mars rotates every 24 hours, 37 minutes, and 22 seconds while Earth takes 23 hours, 56 minutes, and 4 seconds to rotate once. What is the ratio, in seconds, of a Mars day to an Earth day?

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Alex has developed a new interplanetary grandfather clock for a Mars colony with an adjustable length pendulum. For it to keep perfect 24-hour time, The pendulum length is set so the period is 2.000 s here on Earth. (gEarth = 9.81 m/2) a) What is the pendulum's length on Earth? b) The clock will first be set up on the Luna, the Earth's moon. To keep the same 24- hour-a-day time in Luna's gravity (gLuna = 1.635 m/s?), what is the pendulum length? c) Mars rotates every 24 hours, 37 minutes, and 22 seconds while Earth takes 23 hours, 56 minutes, and 4 seconds to rotate once. What is the ratio, in seconds, of a Mars day to an Earth day? d) A Mars "day" of 24 hours would require longer "seconds" special to Mars. Assuming the same ratio holds for seconds as calculated for days, find the length of the pendulum rod needed to adjust the period of the pendulum on Mars to such a longer second. (gMars = 3.721 m/$2)
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