Air is to be dehumidified by condensing the water vapour present in it by cooling at constant pressure. 100m ^ 3 of air at 100 kPa and 300 K contains water vapour which exerts a partial pressure of 4 kPa. Keeping the pressure constant, this air is cooled to 275 K and the condensed water is removed. The partial pressure of water in the air after cooling is found to be 1.8 kPa. Calculate the following: (a) The volume of air after dehumidification in m ^ 3 (b) The mass of water removed in kg
Air is to be dehumidified by condensing the water vapour present in it by cooling at constant pressure. 100m ^ 3 of air at 100 kPa and 300 K contains water vapour which exerts a partial pressure of 4 kPa. Keeping the pressure constant, this air is cooled to 275 K and the condensed water is removed. The partial pressure of water in the air after cooling is found to be 1.8 kPa. Calculate the following: (a) The volume of air after dehumidification in m ^ 3 (b) The mass of water removed in kg
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Air is to be dehumidified by condensing the water vapour present in it by cooling at constant pressure. 100m ^ 3 of air at 100 kPa and 300 K contains water vapour which exerts a partial pressure of 4 kPa. Keeping the pressure constant, this air is cooled to 275 K and the condensed water is removed. The partial pressure of water in the air after cooling is found to be 1.8 kPa. Calculate the following:
(a) The volume of air after dehumidification in m ^ 3
(b) The mass of water removed in kg
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