air-conditioning system is shown in the figure below in which air flows over tubes carrying Refrigerant 134a. Air enters with a volumetric flow rate of (AV)1 = 130 m3/min at 32°C, 1 bar, and exits at 22°C, 0.95 bar. Refrigerant enters the tubes at 5 bar with a quality of 20% and exits at 5 bar, 20°C. Ignoring heat transfer at the outer surface of the air conditioner, and neglecting kinetic and potential energy effects, determine at stead
air-conditioning system is shown in the figure below in which air flows over tubes carrying Refrigerant 134a. Air enters with a volumetric flow rate of (AV)1 = 130 m3/min at 32°C, 1 bar, and exits at 22°C, 0.95 bar. Refrigerant enters the tubes at 5 bar with a quality of 20% and exits at 5 bar, 20°C. Ignoring heat transfer at the outer surface of the air conditioner, and neglecting kinetic and potential energy effects, determine at stead
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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An air-conditioning system is shown in the figure below in which air flows over tubes carrying Refrigerant 134a. Air enters with a volumetric flow rate of (AV)1 = 130 m3/min at 32°C, 1 bar, and exits at 22°C, 0.95 bar. Refrigerant enters the tubes at 5 bar with a quality of 20% and exits at 5 bar, 20°C.
Ignoring heat transfer at the outer surface of the air conditioner, and neglecting kinetic and potential energy effects, determine at steady state:
(a) the mass flow rate of the refrigerant, in kg/min.
(b) the rate of heat transfer, in kJ/min, to the air from the refrigerant.
(a) the mass flow rate of the refrigerant, in kg/min.
(b) the rate of heat transfer, in kJ/min, to the air from the refrigerant.
Transcribed Image Text:Air
P1 = 1 bar
T = 32°C = 305 K
(AV),
3
Refrigerant 134a
R-134a
P3 = 5 bar
Xz = 0.20
4
+
R-134a
P4 = 5 bar
T = 20°C
Air
2+P2 = 0.95 bar
T = 22°C = 295 K
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