Air, at a pressure of 60kPa and a temperature of -20°C, flows at Mach 2.5 over a wedge, which turns the flow through a 4° angle leading to the generation of an oblique shock wave. This oblique shock front impinges on a wall that turns away from the flow by 4° exactly at the point where the oblique shock front impinges on it, i.e., the wall has a sharp convex 4" comer at the point where the incident shock impinges on the wall. If the leading edge of the wedge is I metre above the wall, then how far behind this leading edge would the change in wall angle have to occur; calculate x? M = 25 P- 60 kPa T--20°C h= 1m Shock "cancelled"
Air, at a pressure of 60kPa and a temperature of -20°C, flows at Mach 2.5 over a wedge, which turns the flow through a 4° angle leading to the generation of an oblique shock wave. This oblique shock front impinges on a wall that turns away from the flow by 4° exactly at the point where the oblique shock front impinges on it, i.e., the wall has a sharp convex 4" comer at the point where the incident shock impinges on the wall. If the leading edge of the wedge is I metre above the wall, then how far behind this leading edge would the change in wall angle have to occur; calculate x? M = 25 P- 60 kPa T--20°C h= 1m Shock "cancelled"
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Air, at a pressure of 60kPab and a temperature of -20°C, flows at Mach 2.5 over a wedge, which
turns the flow through a 4° angle leading to the generation of an oblique shock wave. This oblique
shock front impinges on a wall that turns away from the flow by 4° exactly at the point where the
oblique shock front impinges on it, i.e., the wall has a sharp convex 4° cormer at the point where the
incident shock impinges on the wall. If the leading edge of the wedge is I metre above the wall, then
how far behind this leading edge would the change in wall angle have to occur; calculate x?
M = 25
P- 60 kPa
T= -20°C
h= 1m
Shock
"cancelled"](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05d1d185-d29f-4980-80b5-5accfc9e1e6a%2Fb02607ba-79c7-4ef3-8a63-42adaaa7779d%2Fs6v8d1_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Air, at a pressure of 60kPab and a temperature of -20°C, flows at Mach 2.5 over a wedge, which
turns the flow through a 4° angle leading to the generation of an oblique shock wave. This oblique
shock front impinges on a wall that turns away from the flow by 4° exactly at the point where the
oblique shock front impinges on it, i.e., the wall has a sharp convex 4° cormer at the point where the
incident shock impinges on the wall. If the leading edge of the wedge is I metre above the wall, then
how far behind this leading edge would the change in wall angle have to occur; calculate x?
M = 25
P- 60 kPa
T= -20°C
h= 1m
Shock
"cancelled"
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