Part: 2 / 3Part 3 of 3AG=kJmol3 Calculate E, E, and AG for the following cell reaction:3 Zn(s) + 2 Cr³+ (aq) =3Zn²+ (aq) + 2 Cr (s)2+where [Cr³+] = 0.070 M and [Zn²+] = 0.0065 M. Round each of your answers to 2 significant digits.Note: Reference the Standard reduction potentials at 25 °C table for additional information.Note: The Faraday constant is 9.649 × 104Part: 0 / 3Part 1 of 3E° =Part: 1 / 3Part 2 of 3E =VVx10☐x10XXJV.molŚŚ

Answered: AG= kJ mol S

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Chemistry

AG= kJ mol S

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Polymerization Kinetics

Polymerization is a chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that diverge in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes. Polymerization is generally classified into step-growth and chain polymerization. Polymers are categorized into linear polymer and cross-linked polymers that are produced either by condensation or additional polymerization.

Question

Calculate E, E, and AG for the following cell reaction:
3 Zn(s) + 2 Cr³+ (aq) =3Zn²+ (aq) + 2 Cr (s)
2+
where [Cr³+] = 0.070 M and [Zn²+] = 0.0065 M. Round each of your answers to 2 significant digits.
Note: Reference the Standard reduction potentials at 25 °C table for additional information.
Note: The Faraday constant is 9.649 × 104
Part: 0 / 3
Part 1 of 3
E° =
Part: 1 / 3
Part 2 of 3
E =
V
V
x10
☐x10
X
X
J
V.mol
Ś
Ś

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