After surveying a random sample of 300 students in an online degree program, 86% believed that their classes were worth the cost they were paying. The results from a survey of 345 randomly selected students who were in a face-to-face degree program who had also taken some online courses, showed that 84% of them believed those online courses were worth the cost. Construct a 90% confidence interval for the difference

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A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: In a Gallup poll of 804 randomly selected adults living in the 50 U.S. states and the District of…

A: Answer x =466n =804Confidence interval =95%

Q: A research center survey of 2,384 adults found that 1,868 had bought something online. Of these…

A: From the provided information,Sample size (n) = 2384From which 1247 are weekly online…

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A:

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A: Given Data: x=722 n=1762   p^=7221762=0.4098

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A: Given:  n=4026 x=708

Q: In a random sample of 100 customers, the items that customers purchased were tracked. It was found…

A: Given,sample size(n)=100sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: It is given that, x is 311 and n is 400.

Q: A class has 420 students. The final examination is optional—taking it can raise, but cannot lower, a…

A: It is given that sample size (n) is 80 and the number of students would take the final examination…

Q: adults in a recent​ year, 742 made a New​ Year's resolution to eat healthier.   Construct​ 90% and​…

A: The value of z at a 90% confidence level is 1.645, which can be found by using the standard normal…

Q: A sample of 80 respondents was taken to determine whether the clients of an internet provider are…

A: Given that  Sample size (n) = 80 Respondents satisfied with the service (x) = 60 Sample proportion…

Q: In a random sample of 170 customers, 90 ordered chicken sandwiches for lunch. Construct a 94%…

A:

Q: In a survey of 3985 ​adults, 711 oppose allowing transgender students to use the bathrooms of the…

A: Given, n=3985 x=711 To find a confidence interval for a population proportion.

Q: In a survey of 4008 ​adults, 728 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 4052 ​adults, 723 oppose allowing transgender students to use the bathrooms of the…

A: It is given that x = 723 and n= 4,052.

Q: researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 520…

A:

Q: Suppose I wanted to know the proportion of students who are paying attention in class, so I give a…

A: Confidence Interval for Proportion A confidence interval is a statistical method that denotes a…

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: In a survey of 612 randomly selected female college students, 141 report that they had been sexually…

A: Given Information:n=612x=141c=95%=0.95

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Givenx=722n=1762p^=7221762p^=0.4098α=1-0.98=0.02α2=0.01zc=z0.01=2.3263         (from z-table)

Q: in a survey of 2042 adults in a recent​ year, 715 made a New​ Year's resolution to eat healthier.…

A:

Q: sample of 624 applicants to the Durmstrang Institute of Sorcery, 133 were accepted. Construct a 90%…

A: Given that  X=133 , n=624 , p=20%=0.20

Q: In a sample of 300 people, 154 said that they watched news on television. Find the 90% confidence…

A: According to the given information in this question We need to find the 90% confidence interval of…

Q: n a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A:

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…

A: The population proportion (p) will be proportion of high school freshman who reads at or above their…

Q: A survey of 300 women shoppers found that 17% of them shop on impulse. What is the 80% confidence…

A: From the provided information,A survey of 300 women shoppers found that 17% of them shop on impulse.…

Q: In a survey of 3983 ​adults, 747 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to…

A: Given that, In a sports poll, 142 of 500 randomly selected Americans indicated that they consider…

Q: An ice cream shop wants to know how many customers enjoy their newest flavor. 200 randomly selected…

A:

Q: 9. A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence…

A: In a survey of 280 homeless persons showed that 63 were veterans.

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given that, X = 118 N = 200 99% confidence level

Q: In a survey of 1,626,773 U.S. adults, 49,311 personally identified as lesbian, gay, bisexual, or…

A:

Q: As health insurance costs and the number of disabled employees increase, more companies are firing…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: An internet service provider sampled 540 customers and found that 55 of them experienced an…

A:

Q: A random survey of 36 airline passengers indicates that twelve have never flown before. Find a 95%…

A: We have given that,  Sample size (n) = 36 and favorable cases         (X) = 12 Then,  We Will find…

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

A:

Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…

A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326

Q: Assume a nationwide random survey of 800 adults asked about attitudes toward “alternative medicine”…

A: We have given that,  Sample size (n) = 800 and Favorable cases (X) =448 Then,  We will find the 99%…

Q: According to a recent Government survey, 6% of all merchandise sold in the U.S. gets returned.  A…

A: It is given that sample size (n) is 80 and x is 12.

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…