After reducing a 0.4080 g iron to Fe²⁺, it was titrated with 42.72 mL of 0.1211 N KMnO₄ solution. Calculate the percent Fe₃O₄ (231.54 g/mol). The reaction is described by the equation: MnO₄- + 5Fe²⁺ + 8H⁺ → Mn²⁺ + 5Fe³⁺ + 4H₂O *     Choices    50.81%       70.81%       36.77%       97.86%       58.72%

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