Ores are analyzed by dissolving some of the ore and then performing an analysis of a metal (expressed in grams); usually the concentration of the metal is expressed as % of the amount of the ore (in grams) dissolved. An ore containing Sn was dissolved and then titrated with MnO4-. When 14.1960 g was dissolved and titrated with 0.1535 M MnO4- the titration required 35.32 mL to reach the endpoint. What was the % Sn in the ore? 5Sn2+(aq) + 2MnO4-(aq) + 16H+(aq) ↔ 5Sn4+(aq) + 2Mn2+(aq) + 8H2O(l)
Ores are analyzed by dissolving some of the ore and then performing an analysis of a metal (expressed in grams); usually the concentration of the metal is expressed as % of the amount of the ore (in grams) dissolved. An ore containing Sn was dissolved and then titrated with MnO4-. When 14.1960 g was dissolved and titrated with 0.1535 M MnO4- the titration required 35.32 mL to reach the endpoint. What was the % Sn in the ore? 5Sn2+(aq) + 2MnO4-(aq) + 16H+(aq) ↔ 5Sn4+(aq) + 2Mn2+(aq) + 8H2O(l)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Ores are analyzed by dissolving some of the ore and then performing an analysis of a metal (expressed in grams); usually the concentration of the metal is expressed as % of the amount of the ore (in grams) dissolved. An ore containing Sn was dissolved and then titrated with MnO4-. When 14.1960 g was dissolved and titrated with 0.1535 M MnO4- the titration required 35.32 mL to reach the endpoint. What was the % Sn in the ore?
5Sn2+(aq) + 2MnO4-(aq) + 16H+(aq) ↔ 5Sn4+(aq) + 2Mn2+(aq) + 8H2O(l) |
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18.14%
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