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after addition of 25.0 mL of HBr pH = | 4.57 Incorrect after addition of 34.0 mL of HBr pH =| 4.6 Incorrect

after addition of 25.0 mL of HBr pH = | 4.57 Incorrect after addition of 34.0 mL of HBr pH =| 4.6 Incorrect

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the pH for each of the cases in the titration of 25.0 mL of 0.250 M pyridine, C,H,N(aq) with 0.250 M HBr(aq). The Kp of pyridine is 1.7 x 10-9. before addition of any HBr pH = 9.32 after addition of 12.5 mL of HBr pH = 5.23 after addition of 24.0 mL of HBr pH = 3.92 after addition of 25.0 mL of HBr pH =| 4.57 Incorrect after addition of 34.0 mL of HBr pH = | 4.6 Incorrect
Transcribed Image Text:Calculate the pH for each of the cases in the titration of 25.0 mL of 0.250 M pyridine, C,H,N(aq) with 0.250 M HBr(aq). The Kp of pyridine is 1.7 x 10-9. before addition of any HBr pH = 9.32 after addition of 12.5 mL of HBr pH = 5.23 after addition of 24.0 mL of HBr pH = 3.92 after addition of 25.0 mL of HBr pH =| 4.57 Incorrect after addition of 34.0 mL of HBr pH = | 4.6 Incorrect
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Step 1

The question is based on the titration of weak base pyridine with strong acid hydrobromic acid.

we have to determine pH at various points of the titration.

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