Jastruction:• Can you tell whether the net flux through the Gaussian surface is positive, negalive.A The Caussian cylinder is in a uniform electric field of magnitude E, alignod wich thear anwer abaut the net flux only on a qualitative arguments about the mognitude of the flux throughavtric fields. The end caps are labeled A and C and the side surface is labeled B. In each case, baseIn the following questions, a Gaussian cylinder with radius a and length lis placed in variousend cups and side of the surfaceglinder axis,• Find the sign and magnitude of the flux through:Surface A:Surface B:Surface C:akthe net fux through the Gaussian surface positive, negative, or zero?| The Gaussian cylinder enckoses a negative charge. (The field from part A is removod)• Find the sign of the flux through:Surface A:Surface B:Surface C:• Is the net flux through the Gaussian surface positive, negative, or zero?C. The Gaussian cylinder encloses opposite charges of equal magnitude. (The chargesure on the axis of the cylinder and cquidistant from the center.)• Find the sign of the flux through:Surface A:Surface B:Surface C:* Is the net flux through the Gaussian surface positive, negative, or zero?D. A posicive charge is located above the Gaussian cylinder.• Find the sign of the flux through:Surface A:Surface B:Surface C:or zero? Explain.

We know that the formula of the electric field is given as ϕ= ∫E.dAϕ= qinε0 where the E is the…

aer about the net fluex only on a qualitative arguments about the magnitade of the fha throw In the The Gaussian cylinder is in a uniform clectric field of magniude E, aligned with the • Find the sign and magnitode of the flux through: rie fields. The end caps are labeled A and C and the sidc surface is labeled B. In each case, base dius a and length 1l is placed in various glinder axis. Suface R.

aer about the net fluex only on a qualitative arguments about the magnitade of the fha throw In the The Gaussian cylinder is in a uniform clectric field of magniude E, aligned with the • Find the sign and magnitode of the flux through: rie fields. The end caps are labeled A and C and the sidc surface is labeled B. In each case, base dius a and length 1l is placed in various glinder axis. Suface R.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Problem An electric charge Q is distributed uniformly along a thick and enormously long conducting wire with radius R and length L. Using Gauss's law, what is the electric field at distance r perpendicular to the wire? (Consider the cases inside and outside the wire) Solution To find the electric field inside at r distance from the wire we will use the Gauss's law which is expressed as We will choose a symmetric Gaussian surface, which is the surface a cylinder excluding its ends, then evaluate the dot product to obtain A = (Equation 1) Case 1: Inside the wire Since, r falls inside the wire, then all the enclosed charge must be: denc On the other hand, the Gaussian surface inside the wire is given by A = Using Equation 1, the electric field in simplified form is E =
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